Question

我有一个类似下面的数组

_combinedBirthdates(
"03/12/2013",
"03/12/2013",
"08/13/1990",
"12/09/1989",
"02/06",
"09/08",
"03/02/1990",
"08/22/1989",
"03/02",
"05/13",
"10/16",
"07/08",
"08/31/1990",
"04/14/1992",
"12/15/1905",
"08/14/1989",
"10/07/1987",
"07/25",
"07/17/1989",
"03/24/1987",
"07/28/1988",
"01/21/1990",
"10/13"

）

这一切都是NSString

我正在尝试从此处创建一个新数组，其中包含的内容如下所示

（特定生日的剩余天数）（我们将使用上述日期数组来计算当前日期，我们将查找剩余天数） _newarray（ “125”， “100”， “65”，直到这样结束.. ）

我正在使用以下代码

unsigned int unitFlags =  NSDayCalendarUnit;
NSCalendar *currCalendar = [[NSCalendar alloc]
                            initWithCalendarIdentifier:NSGregorianCalendar];


NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];

[dateFormatter setDateStyle:NSDateFormatterShortStyle];
NSLog(@" currCalendar%@",currCalendar);

NSMutableArray * _newarray = [[NSMutableArray alloc] init];
for (NSString * str in _combinedBirthdates){

    NSDate * toDate = [dateFormatter dateFromString:str];
    NSDateComponents *daysInfo = [currCalendar components:unitFlags fromDate:[NSDate date]  toDate:toDate  options:0];
    int days = [daysInfo day];
    [_newarray addObject:[NSString stringWithFormat:@"%d",days]];
}
NSLog(@" _newarray%@",_newarray);

当我打印_newarray时，这就是我得到的输出plz帮助我谢谢你

_newlymadeArray(
"-1",
"-1",
"-8248",
"-8495",
"-4454",
"-4454",
"-8412",
"-8604",
"-4454",
"-4454",
"-4454",
"-4454",
"-8230",
"-7638",
"-39170",
"-8612",
"-9289",
"-4454",
"-8640",
"-9486",
"-8994",
"-8452",
"-4454",
"-2072",
"-888",
"-8315"
)

Answer 1

请尝试使用此。我认为这个可以帮到你。

NSDateFormatter *tempFormatter = [[NSDateFormatter alloc]init];
    [tempFormatter setDateFormat:@"dd/MM/yyyy"];

    NSString *str = [tempFormatter stringFromDate:@"yourStartDate"];
    NSDate *startdate = [tempFormatter dateFromString:str];

    str = [tempFormatter stringFromDate:@"yourEndDate"];
    NSDate *endDate = [tempFormatter dateFromString:str];

    int i = [startdate timeIntervalSince1970];
    int j = [toDate timeIntervalSince1970];

    double X = j-i;

    int days=(int)((double)X/(3600.0*24.00));

Answer 2

使用下面的代码来比较两个日期以相同的格式传递两个日期

NSDateFormatter *dateformat = [[NSDateFormatter alloc]init];
[dateformat setDateFormat:@"dd/MM/yyyy"];
NSString *StrDate1 = [dateformat stringFromDate:[NSDate date]];
NSString *StrDate2 = [dateformat stringFromDate:date2];
NSDate *firstDate = [dateformat dateFromString:StrDate1];
NSDate *secondDate = [dateformat dateFromString:StrDate2];
NSTimeInterval lastDiff = [firstDate timeIntervalSinceNow];
NSTimeInterval todaysDiff = [secondDate timeIntervalSinceNow];
NSTimeInterval dateDiff = todaysDiff - lastDiff;
int day = dateDiff/(3600*24);

 // days are remaining

在for循环中使用此功能，您将关闭剩余天数

从一系列日期中发现日子仍然存在

2 个答案: