Question

我正在建立一个在线西班牙语词典。我从另一个网站合法地获得了定义。对于用户可以搜索的特定单词，出现建议列表。如果您点击任何建议的字词，系统会弹出错误页面：http://verbum.xtrweb.com/verbumpost.php?word=boedo&word0=hola。如何使列出的单词通过下面粘贴的代码运行：（1）检索定义（2）更改样式。我知道每个建议的单词（inspect元素）都有一个唯一的URL。如果您将该代码与原始网站的网址参数粘贴在一起，您就会得到我需要的内容：

“http://lema.rae.es/drae/srv/search?id=AVNYdnea1DXX2EH9E2mb”

最多“srv /”属于网站

其余部分来自特定的单词（在这种情况下，第一个建议，“bordar”

过程：

    <?php
    $words = array('word','word0','word1','word2','word3','word4','word5','word6','word7','word7','word9',     
    'word10','word11','word12',
    'word13','word14','word15');                        
    function url_decode($string){
    return urldecode(utf8_decode($string));
    }

    // we'll use this later on for loading the files.
    $baseUrl = 'http://lema.rae.es/drae/srv/search?val=';

    // string to replace in the head.
    $cssReplace = <<<EOT

    <style type="text/css">
          //blabla
    </style>
    </head>
    EOT;

   // string to remove in the document.
   $spanRemove = '<span class="f"><b>.</b></span>';
   $styleRemove = 

   // use for printing out the result ID.
   $resultIndex = 0;

   // loop through the words we defined above
   // load the respective file, and print it out.
   foreach($words as $word) {
// check if the request with
// the given word exists. If not,
// continue to the next word
if(!isset($_REQUEST[$word]))
    continue;

// load the contents of the base url and requested word.
$contents = file_get_contents($baseUrl . urldecode(utf8_decode($_REQUEST[$word])));
// replace the data defined above.
$contents = str_replace('</head>', $cssReplace, $contents);
$contents = str_replace($spanRemove,"", $contents);

$data = preg_replace('/(search?[\d\w]+)/','http://lema.rae.es/drae/srv/\1', $data);

// print out the result with the result index.
// ++$resultIndex simply returns the value of 
// $resultIndex after adding one to it.
echo "<div id='results' style='
      //bla bla
      }
        ?>

Answer 1

我认为我不理解您的问题，但我确实看到您在未初始化的变量上调用preg_replace - $ data。

也许你想要这个呢？

 $data = preg_replace('/(search?[\d\w]+)/','http://lema.rae.es/drae/srv/\1', $contents);

就像我说的那样，我并不完全理解你的问题，但我确实认为这是一个潜在的问题。

编辑：

从您的评论中，您似乎想要将被点击的链接的href附加到基本网址并请求该网页的数据。你能用jQuery吗？像这样：

var baseUrl = "http://lema.rae.es/drae/srv/"; // base url

//click function that binds to all anchors within a list item within a ul. in order
//to get more precise, you may need to add some classes or ids
$('ul li a').click(function(){
     var src = $(this).prop('href'); //this grabs the href property of the anchor
     $(this).find('span').css('propery', 'change to this'); //change css property of span child of this anchor
     //or if you want to add a class with styles to the element
     $(this).find('span').addClass('class name');

     //ajax request to get page data
     $.ajax({
         type: 'POST',
         url: baseUrl+src  //appending the query to the base url
     }).done(function(data){
         //append the returned html to a div, or any element you desire
         $('#myelement').append(data);
     });
});

希望这会有所帮助。如果您需要任何jQuery帮助，请告诉我。

复制Word并将其另存为变量

1 个答案: