Question

当我尝试使持久句柄变弱时，为什么不调用WeakReference回调？请参阅以下示例：

void myWeakReferenceCallback(v8::Persistent<v8::Value> theValue, void *theParameter)
{
    fprintf(stdout, "myWeakReferenceCallback");
}

void testWeakReferenceCallback()
{
    v8::Persistent<v8::Value> persistent_value;
    {
        v8::Persistent<v8::Context> context = v8::Context::New();
        v8::Context::Scope context_scope(context);
        v8::HandleScope handle_scope;
        v8::Local<v8::Value> local_value = v8::NumberObject::New(5.0);
        persistent_value = v8::Persistent<v8::Value>::New(local_value);
        persistent_value.MakeWeak(NULL, myWeakReferenceCallback);
        context.Dispose();
    }
    persistent_value.Dispose();
}

Answer 1

我相信有两个问题：

在V8有机会调用回调之前，你正在处理弱句柄。您需要将内部处理回调。
V8在执行GC之前不会调用弱句柄回调。

试试这个：

void myWeakReferenceCallback(v8::Persistent<v8::Value> theValue, void *theParameter)
{
    fprintf(stdout, "myWeakReferenceCallback");
    theValue.Dispose();
}

void testWeakReferenceCallback()
{
    v8::Persistent<v8::Value> persistent_value;
    {
        v8::Persistent<v8::Context> context = v8::Context::New();
        v8::Context::Scope context_scope(context);
        v8::HandleScope handle_scope;
        v8::Local<v8::Value> local_value = v8::NumberObject::New(5.0);
        persistent_value = v8::Persistent<v8::Value>::New(local_value);
        persistent_value.MakeWeak(NULL, myWeakReferenceCallback);
        context.Dispose();
    }
    //persistent_value.Dispose();
    while (!v8::V8::IdleNotification()); // force GC
}

V8：为什么不调用WeakReference回调？

1 个答案: