我一直在开始使用Microsoft Windows Azure存储表。一切似乎工作正常 - 我可以创建表并插入行,有一个问题 - 我似乎无法插入除预定义的行键字段之外的任何行,即“PartitionKey”,“RowKey”,和“时间戳”。
在下面的示例代码中,它只是MVC应用程序中最简单的“Hello World”(我唯一添加的是控制器),输出显示预期值位于分区键和行键中,但我试图插入的“测试字段”仍然是空的。
当进入调试器中的代码时,我可以看到当第一个table.Execute()发生时,我试图设置的测试字段的名称和值就位。但由于某种原因,它实际上并没有进入表格。
任何帮助都非常感激。
using System;
using System.Configuration;
using Microsoft.WindowsAzure.Storage;
using Microsoft.WindowsAzure.Storage.Table;
using System.Web.Mvc;
namespace HelloWorldApp.Controllers
{
public class TestEntity : TableEntity
{
public string TestField;
public TestEntity() { }
public TestEntity(string partitionKey, string rowKey, string testField)
{
PartitionKey = partitionKey;
RowKey = rowKey;
TestField = testField;
}
}
public class HomeController : Controller
{
public string Index()
{
CloudStorageAccount storageAccount = CloudStorageAccount.Parse(ConfigurationManager.ConnectionStrings["StorageConnectionString"].ConnectionString);
if (storageAccount == null)
return "Storage Account is Null";
CloudTableClient tableClient = storageAccount.CreateCloudTableClient();
if (tableClient == null)
return "Table Client is Null";
CloudTable table = tableClient.GetTableReference("TestTable");
if (table == null)
return "Table is Null";
table.CreateIfNotExists();
var entity = new TestEntity("MyTestPartitionKey", "MyTestRowKey", "MyTestMessage");
var doInsert = TableOperation.Insert(entity);
if (doInsert == null)
return "Insert Operation is Null";
// In debugger, I have confirmed that doInsert does include the field TestField="MyTestMessage", yet it doesn't seem to find its way into the table.
table.Execute(doInsert);
var doRetrieve = TableOperation.Retrieve<TestEntity>("MyTestPartitionKey", "MyTestRowKey");
TableResult retrievedResult = table.Execute(doRetrieve);
if (retrievedResult == null)
return "Retrieved no rows";
string retPartitionKey = ((TestEntity) retrievedResult.Result).PartitionKey;
string retRowKey = ((TestEntity) retrievedResult.Result).RowKey;
string retTestMessage = ((TestEntity) retrievedResult.Result).TestField;
return String.Format("Partition: {0}, Row: {1}, TestMessage {2}, remember to delete table.", retPartitionKey, retRowKey, retTestMessage);
}
}
}
答案 0 :(得分:2)
您是否尝试使用get; set;?
将TestField转换为属性为TestEntity试用此代码:
public class TestEntity : TableEntity
{
public string TestField { get; set; }
public TestEntity() { }
public TestEntity(string partitionKey, string rowKey, string testField)
{
PartitionKey = partitionKey;
RowKey = rowKey;
TestField = testField;
}
}