Question

我不确定这个案例陈述的序列有什么问题。我已经在线查看，语法似乎是正确的，但我收到错误丢失的关键字。任何帮助将不胜感激！

CASE 
when A = '1' then
         when sequence_number = 5 then 9
         when sequence_number = 6 then 9
         end
 when A = '2' then
       when sequence_number = 5 then 9
       when sequence_number = 6 then 9
       end
  when A = '3' then
        when sequence_number =7 then 9
        when sequence_number =8 then 9
        end
else T.number
end as number

Answer 1

您需要在每个分支中使用第二个CASE语句，否则您需要结合条件

CASE 
when A = '1' and sequence_number = 5 then 9
when A = '1' and sequence_number = 6 then 9
when A = '2' and sequence_number = 5 then 9
...
else T.number
end as number

或

CASE 
when A = '1' then
         case when sequence_number = 5 then 9
              when sequence_number = 6 then 9
         end
when A = '2' then
       case when sequence_number = 5 then 9
            when sequence_number = 6 then 9
       end
when A = '3' then
        case when sequence_number =7 then 9
             when sequence_number =8 then 9
        end
else T.number
end as number

Answer 2

最简单的选择似乎是：

 case 
   when (A in (1,2) and sequence_number in (5,6)) or
        (A in (3  ) and sequence_number in (7,8))
   then 9
   else t.number
 end

Answer 3

@mikeb是正确的 - 你需要一个额外的CASE。

我在测试时遇到了Number列的问题;只是猜测，但也许甲骨文作为一个保留字窒息？如果您和我一样获得ORA-01747: invalid user.table.column, table.column, or column specification例外，请将其更改为Num或TheNumber。

这是更新的CASE：

CASE
when A = '1' then
       case
       when sequence_number = 5 then 9
       when sequence_number = 6 then 9
       end
when A = '2' then
       case
       when sequence_number = 5 then 9
       when sequence_number = 6 then 9
       end
when A = '3' then
       case
       when sequence_number =7 then 9
       when sequence_number =8 then 9
       end
else T.number
end as number

SELECT CASE中缺少关键字

3 个答案: