Question

我们正在尝试使用＆＃34;非规范化数据＆＃34;导出excel表。到xml。表格标题如下：

| AssetManager Code | AssetManager Date | Portfolio Code | Portfolio Name | MarketValue | NetCashFlow | Field | Field Code | Field Name |

AssetManager代码和AssetManager日期始终相同，其余列包含可变数据。

以下是我们想要的xml输出示例：

<AssetManager Code="PFM" Date="20130117">                   
    <Portfolios>            
        <Portfolio Code="CC PSP" Name="Consilium Capital">      
            <MarketValue>5548056.51</MarketValue>   
            <NetCashFlow>0</NetCashFlow>    
            <UserFields>    
                <Field Code="AM UCGT" Name="AM daily Unrealised CG">4375</Field>
            </UserFields>   
        </Portfolio>        
        <Portfolio Code="MM (FC)" Name="Money Market UT (FC)">      
            <MarketValue>28975149.6500735</MarketValue> 
            <NetCashFlow>0</NetCashFlow>    
            <UserFields>    
                <Field Code="UCGT" Name="AM daily Unrealised CG">0</Field>
            </UserFields>   
        </Portfolio>        
    </Portfolios>           
</AssetManager>

我们的xsd文件包含映射：

<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:element name="AssetManager">
    <xs:complexType>
        <xs:sequence>
                    <xs:element ref="Portfolios" />
            </xs:sequence>
        <xs:attribute name="Code" type="xs:string"/>
            <xs:attribute name="Date" type="xs:string"/>
    </xs:complexType>
</xs:element>
<xs:complexType name="FieldType">
    <xs:simpleContent>
        <xs:extension base="xs:decimal">
            <xs:attribute name="Code" type="xs:string"/>
                <xs:attribute name="Name" type="xs:string"/>
        </xs:extension>
    </xs:simpleContent>
</xs:complexType>
<xs:element name="Portfolios">
  <xs:complexType>
    <xs:sequence>
      <xs:element name="Portfolio">
    <xs:complexType>
      <xs:sequence>
        <xs:element name="MarketValue" type="xs:decimal"/>
        <xs:element name="NetCashFlow" type="xs:decimal"/>
        <xs:element name="UserFields">
          <xs:complexType>
            <xs:sequence>
                    <xs:element name="Field" type="FieldType"/>
            </xs:sequence>
          </xs:complexType>
        </xs:element>
      </xs:sequence>
      <xs:attribute name="Code" type="xs:string"/>
      <xs:attribute name="Name" type="xs:string"/>
    </xs:complexType>
              </xs:element>
            </xs:sequence>
    </xs:complexType>
  </xs:element>
</xs:schema>

至少我们想知道为什么excel认为数据非规范化了？

非常感谢任何帮助。

Answer 1

首先，发布的XSD存在问题。 Portfolio应该将maxOccurs设置为大于1的值 - 否则您不匹配示例XML，并且在Excel中验证地图时不会出现“非规范化数据”错误。

This article应该解释您使用Excel地图时遇到的常见错误 - 包括您的错误。

我猜你所做的是拖放根 - 这对重复元素不起作用。

你可以解决我在下面所做的事情;它可能不适用于你的具体例子，但它应该给你一个想法。

修改您的XSD以考虑重复粒子：

<?xml version="1.0" encoding="UTF-8"?>
<!-- XML Schema generated by QTAssistant/XSD Module (http://www.paschidev.com) -->
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">
    <xs:element name="AssetManager">
        <xs:complexType>
            <xs:sequence>
                <xs:element ref="Portfolios"/>
            </xs:sequence>
            <xs:attribute name="Code" type="xs:string"/>
            <xs:attribute name="Date" type="xs:string"/>
        </xs:complexType>
    </xs:element>
    <xs:complexType name="FieldType">
        <xs:simpleContent>
            <xs:extension base="xs:decimal">
                <xs:attribute name="Code" type="xs:string"/>
                <xs:attribute name="Name" type="xs:string"/>
            </xs:extension>
        </xs:simpleContent>
    </xs:complexType>
    <xs:element name="Portfolios">
        <xs:complexType>
            <xs:sequence>
                <xs:element name="Portfolio" minOccurs="0" maxOccurs="unbounded">
                    <xs:complexType>
                        <xs:sequence>
                            <xs:element name="MarketValue" type="xs:decimal"/>
                            <xs:element name="NetCashFlow" type="xs:decimal"/>
                            <xs:element name="UserFields">
                                <xs:complexType>
                                    <xs:sequence>
                                        <xs:element name="Field" type="FieldType"/>
                                    </xs:sequence>
                                </xs:complexType>
                            </xs:element>
                        </xs:sequence>
                        <xs:attribute name="Code" type="xs:string"/>
                        <xs:attribute name="Name" type="xs:string"/>
                    </xs:complexType>
                </xs:element>
            </xs:sequence>
        </xs:complexType>
    </xs:element>
</xs:schema>

仅在第一张纸上拖动代码和日期;如果你愿意，可以将其重命名为其他内容。

enter image description here

将投资组合拖到另一张表。

enter image description here

填写一些数据并导出;这就是我得到的：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<AssetManager Code="a" Date="b">
    <Portfolios>
        <Portfolio Code="aa" Name="bb">
            <MarketValue>10</MarketValue>
            <NetCashFlow>100</NetCashFlow>
            <UserFields>
                <Field/>
            </UserFields>
        </Portfolio>
        <Portfolio Code="aa" Name="bb">
            <MarketValue>10</MarketValue>
            <NetCashFlow>100</NetCashFlow>
            <UserFields>
                <Field/>
            </UserFields>
        </Portfolio>
    </Portfolios>
</AssetManager>

看起来非常接近。如果没有解决方案本身，那么它应该可以帮助你前进，然后进行调查。

Answer 2

我编写了一些代码来将数据透视表写入原始XML格式。在这里，我没有遵循任何预先设置的模式，只是将数据透视表heirarchy写入XML。为此，您必须使用大纲表单但不紧凑（每个新级别应该开始一个新列）。此外，代码不需要小计或总计，并且预期数据字段中只有一级数字数据。

您的PT将采用可接受的XML格式，其节点根据PT标头命名，但子组标题的名称为“name =”无效。所以你得到的XML就像 - “这里的文件夹内容”。

见下面的代码：另一个警告，这还没有得到很好的清理。有些行永远不会受到旧代码实现的影响。此外，在调试结束之前有一个停止 - 如果您需要更改输出并重做文件写入步骤。输出在C：驱动器中写为名为“txt.txt”的文本文件。

根据需要进行编辑和重复使用。

Private Sub XMLWriter()
Dim sht As Worksheet: Set sht = ActiveSheet
    'Debug.Print "The current Sheet is " & sht.Name
Dim pt As PivotTable: Set pt = sht.PivotTables(1)
    'Debug.Print "Pivot Table name is " & pt.Name
Dim begin As String: begin = pt.TableRange1.Cells(1, 1).Address

Dim rows As Integer: rows = pt.TableRange1.rows.Count
Dim LastCell As Range: Set LastCell = pt.TableRange1.Cells(rows, 1)

 If LastCell.PivotCell.PivotCellType = xlPivotCellGrandTotal Then Set LastCell = LastCell.Offset(-1, 0)
 If LastCell.PivotCell.PivotCellType = xlPivotCellSubtotal Then Stop 'not implemented routine does not expect subtotals in rows - (will not create good xml)

Dim LastRow As Integer: LastRow = LastCell.Row

Dim celly As Range: Set celly = sht.Range(begin)
Dim level As Integer: level = 1
Dim levels As Integer: levels = 0 ' PRECEEDING CODE INITIALIZED VARIABLES - Depends on Pivot table in active worksheet (first on sheet, assumes only one on sheet)

Do 'determines nesting depth
    If celly.Offset(0, levels + 1).Value = "" Then
        levels = levels + 1
        Exit Do
    Else: levels = levels + 1
    End If
Loop
'Stop
Dim dataFieldPresent As Boolean
Dim ShutDown As Boolean
If celly.Offset(levels - 1, levels - 1).PivotCell.PivotCellType = xlPivotCellValue Then
levels = levels - 1
dataFieldPresent = True
End If
'Stop


Dim ary() As String ' initializes array
ReDim ary(1 To levels, 7) As String ' based on nesting depth, seven placeholders set to accomadate data
Dim n As Integer
For n = LBound(ary) To UBound(ary)      ' populates 'folder' names from pivottable headings
    ary(n, 0) = celly.Offset(0, n - 1).Value  ' 0 based folder holds name, or already completed xml group's string/data
    ary(n, 1) = gettabs(n) & Cap(ary(n, 0))          ' 1 based folder holds node's'front cap' following xml syntax
    ary(n, 2) = Cap("/" & ary(n, 0)) & vbCrLf   ' 2 based folder holds 'end cap' to close node
    ary(n, 0) = ""
Next

Set celly = celly.Offset(1, 0)
If celly.Value = "" Then Stop ' error occurred, there must be a cell in first column position at first row under Row Heading

ary(level, 3) = nameElement(celly.Value) & vbCrLf ' get value in current cell to name folder   'ary(level, 4) = nameElement("/" & celly.Value) ' level 4 was created for old implementation, no longer used

Dim tabs As String
'Stop
'tabs = gettabs(level)
ary(level, 6) = ary(level, 2) & vbCrLf
ary(level, 5) = ary(level, 1) & ary(level, 3) & vbCrLf

Dim lvlref As Integer: lvlref = 1
Dim addcrlf As String: addcrlf = vbCrLf

Do
    Set celly = celly.Offset(1, -(celly.Column - 1))
'    If celly.Row = 780 Then Stop

    If celly.Row = LastRow Then ShutDown = True


    If celly.Value = "Liabilities" Then Stop
    If Not celly.Value = "" Then
        closetoplevel
        level = 1
        ary = levelup(ary, level, lvlref, levels)
            ary(level, 3) = nameElement(celly.Value) & vbCrLf
 '           ary(level, 4) = nameElement("/" & celly.Value)
            ary(level, 5) = ary(level, 5) & gettabs(level) & ary(level, 3)
            ary(level, 6) = ary(level, 3)
            ary(level, 7) = celly.Value
        writeout ary(1, 0)
'        Stop
    Else
        level = 2
        Do
            Set celly = celly.Offset(0, 1)
             On Error GoTo Term:
             Nam = celly.PivotCell.PivotCellType ' error trap - should always be in pivot table
            On Error GoTo 0
            If celly.Value = "" Then
                level = level + 1
            Else
                Exit Do
            End If
        Loop

        getPosition (celly.Cells(1))

'        If level = lvlref And level > 2 Then Stop ' update: seems to work fine after refactoring code originally ('not implemented - code does not expect given schema structure"
        If level < lvlref Then
            'Stop
            ary = levelup(ary, level, lvlref, levels)
            'getPosition (celly.Cells(1))
            'Stop
            lvlref = level - 1
            GoTo ReInsertionPoint:


        Else


ReInsertionPoint:







            If level = levels Then
                addcrlf = ""
            Else: addcrlf = vbCrLf
            End If

            ary(level, 3) = nameElement(celly.Value) & addcrlf
            If level = levels And dataFieldPresent = True Then
'                Stop
                ary(level, 3) = ary(level, 3) & CStr(celly.Offset(0, 1).Value)
            End If
            ary(level, 5) = ary(level, 5) & ary(level, 3)
            ary(level, 6) = ary(level, 3)
            ary(level, 7) = celly.Value

         If level = levels Then ' XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX  not operating properly failing to add last item (number & accoiunt) of each section
'            Stop

                Dim nextlevel As Integer: nextlevel = 1
                'Stop
                Dim nextlvlcell As Range: Set nextlvlcell = celly.Offset(1, -(level - 1))
                Debug.Print nextlvlcell.Address
                Do
                    If nextlvlcell.Value = "" Then
                        If nextlvlcell.Row > LastRow Then
                            nextlevel = 1
                            GoTo Closure:
                        Else
                            Set nextlvlcell = nextlvlcell.Offset(0, 1)
                            nextlevel = nextlevel + 1
                        End If
                    Else: Exit Do
                    End If
                Loop
                Debug.Print nextlvlcell.Address
                If level - nextlevel > 1 Then
Closure:
                    'Stop
                    ary = pushup(ary(), level, levels, lvlref)
                    'Stop
                    ary = levelup(ary(), level - 1, levels, lvlref)
                Else

                    ary = pushup(ary, level, levels, lvlref)
                End If
            End If

        'Stop

        End If
    End If
lvlref = level
If ShutDown = True Then
    level = 1
    ary = levelup(ary, level, lvlref, levels)
    Exit Do
End If
Loop

writeout "<?xml version=""1.0"" encoding=""UTF-8"" standalone=""yes""?>" & vbCrLf & "<Root xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"">" & vbCrLf & ary(1, 0) & "</Root>"

Stop
End
Term:
Stop

writeout "<?xml version=""1.0"" encoding=""UTF-8"" standalone=""yes""?>" & vbCrLf & "<Root xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"">" & vbCrLf & "<xmldoc>" & vbCrLf & ary(1, 0) & "</xmldoc>" & vbCrLf & "</Root>"
'writeout (ary(1, 0))
Stop
Exit Sub
'created by derik bingner Jan 2014 www.dbexcelaccounting.blogspot.com

End Sub
Private Sub getPosition(x As Range)
Debug.Print "Cell addy is " & x.Address & ". Cell level and text is " & x.Column & " - " & x.Value
End Sub
Private Function gettabs(x As Integer, Optional y As Integer) As String
For n = 1 To (x) ' - y) old implementation allowed offsets
gettabs = vbTab & "" & gettabs
Next
'If ((x * 2) - y) = 8 Then Stop

End Function

Private Function cnam(c As Range)
cnam = c.Value
End Function
Private Function Cap(x As String) As String
If Left(x, 1) = "/" Then
Cap = "</" & Right(x, Len(x) - 1) & ">"
Else: Cap = "<" & x & " name="""
End If
End Function
Private Function nameElement(x As String) As String
nameElement = x & """>"
End Function

Private Sub closetoplevel()
'Stop
'not implemented
End Sub

Private Function pushup(r() As String, l As Integer, s As Integer, ref As Integer)
Dim x As Integer: x = ref - l - 1
'Stop



'If ref <> s Then
'    MsgBox "error, structure issue - not implemented"
'    Stop
'End If
Dim y As Integer
If x > 1 Then ' tests if this function needs to be run recursively to step up multiple levels
    For y = 1 To x - 1
    Dim groupnumber As Integer
    'Stop
    If y <> 2 And InStr(1, r(l + 1, 0), "<") > 0 Then
        groupnumber = 2
    Else: groupnumber = 2 + y - 1
    End If
    'If groupnumber = 2 Then Stop
    Call rlevelup(r, l + (x - y), s, ref, groupnumber) ' recursive section
    'Stop
    Next
End If
'Stop
If r(l, 5) = r(l, 3) Then ' this triggers for first item in group
    'Stop
    r(l, 5) = r(l, 1) & r(l, 5) & r(l, 2)
Else
    If y = 0 Then
    r(l, 5) = r(l, 1) & r(l, 5) & r(l, 2) & vbCrLf
    Stop
    Else
        r(l, 5) = r(l, 5) & vbCrLf & r(l + 1, 5) & vbCrLf & gettabs(l, -1) & r(l, 4) & vbCrLf
'        Stop
    End If
End If

'Debug.Print r(l, 5)
Dim PlaceHolder As String: PlaceHolder = r(l, 0)

    If Left(PlaceHolder, 1) = vbTab Or Left(PlaceHolder, 4) = "    " Or Left(PlaceHolder, 1) = "<" Then
        'Debug.Print PlaceHolder
    Else
        PlaceHolder = ""
    End If

r(l, 0) = PlaceHolder & r(l, 5)
'Stop
For n = LBound(r) To UBound(r)
    If n >= l Then
        For i = 3 To 7
            If r(n, i) <> r(l, 5) Then r(n, i) = ""
        Next
    End If
Next

r(l, 3) = r(l, 5)
r(l, 5) = ""


'Stop
'not implemented

pushup = r
End Function

Private Function levelup(r() As String, l As Integer, s As Integer, ref As Integer)
Dim x As Integer: x = s - l - 1
'If x > 3 Then Stop
'r = pushup(r(), s - 1, s, ref)


'If ref <> s Then
'    MsgBox "error, structure issue - not implemented"
'    Stop
'End If
Dim y As Integer
If x > 1 Then ' tests if this function needs to be run recursively to step up multiple levels
    For y = 1 To x - 1
    Dim groupnumber As Integer
    'Stop
    If y <> 2 And InStr(1, r(l + 1, 0), "<") > 0 Then
        groupnumber = 2
    Else: groupnumber = 2 + y - 1
    End If
'Stop
    'If groupnumber = 2 Then Stop
    Call rlevelup(r, l + (x - y), s, ref, groupnumber) ' recursive section
    'Stop
    Next
End If
'Stop
If r(l, 5) = r(l, 3) Then ' this triggers for first item in group
    'Stop
    r(l, 5) = r(l, 1) & r(l, 5) & gettabs(l) & r(l, 2) & vbCrLf
Else
    If y = 0 Then
    r(l, 5) = r(l, 1) & r(l, 5) & gettabs(l) & r(l, 2) & vbCrLf
    Stop
    Else
        r(l, 5) = r(l, 5) & vbCrLf & r(l + 1, 5) & vbCrLf & gettabs(l, -1) & r(l, 4) & vbCrLf
'        Stop
    End If
End If

'Debug.Print r(l, 5)
Dim PlaceHolder As String: PlaceHolder = r(l, 0)

    If Left(PlaceHolder, 1) = vbTab Or Left(PlaceHolder, 4) = "    " Or Left(PlaceHolder, 1) = "<" Then
        'Debug.Print PlaceHolder
    Else
        PlaceHolder = ""
    End If

r(l, 0) = PlaceHolder & r(l, 1) & r(l, 3) & r(l + 1, 0) & gettabs(l) & r(l, 2)
r(l + 1, 0) = ""
'Stop
For n = LBound(r) To UBound(r)
    If n >= l Then
        For i = 3 To 7
            If r(n, i) <> r(l, 5) Then r(n, i) = ""
        Next
    End If
Next

'r(l, 3) = r(l, 5)
r(l, 5) = ""


'Stop
'not implemented

levelup = r
End Function




Private Function rlevelup(r() As String, l As Integer, s As Integer, ref As Integer, Optional groupnumber As Integer)
Dim x As Integer: x = ref - l - 1
'Stop
'called by level up


'If ref <> s Then
'    MsgBox "error, structure issue - not implemented"
'    Stop
'End If
Dim y As Integer
If x > 1 Then ' tests if this function needs to be run recursively to step up multiple levels
    For y = 1 To x - 1
    'Dim groupnumber As Integer
    'Stop
    'If y <> 2 And InStr(1, r(l + 1, 0), "<") > 0 Then
        groupnumber = 2
    'Else: groupnumber = 2 + y - 1
    'End If
    'If groupnumber = 2 Then Stop
    'Call rpushup(r, l + (x - y), s, ref, groupnumber) ' recursive section
    'Stop
    Next
End If
'Stop
If r(l, 5) = r(l, 3) Then ' this triggers for first item in group
    'Stop
    r(l, 5) = r(l, 1) & r(l, 5) & gettabs(l) & r(l, 2) & vbCrLf
Else
    If y = 0 Then
    r(l, 5) = r(l, 1) & r(l, 5) & gettabs(l) & r(l, 2) & vbCrLf
    Stop ' delete this comment when stop hit programmatically - may be deletable
    Else
        r(l, 5) = r(l, 5) & vbCrLf & r(l + 1, 5) & vbCrLf & gettabs(l, -1) & r(l, 4) & vbCrLf
'        Stop
    End If
End If

'Debug.Print r(l, 5)
Dim PlaceHolder As String: PlaceHolder = r(l, 0)

    If Left(PlaceHolder, 1) = vbTab Or Left(PlaceHolder, 4) = "    " Or Left(PlaceHolder, 1) = "<" Then
        'Debug.Print PlaceHolder
    Else
        PlaceHolder = ""
    End If

r(l, 0) = PlaceHolder & r(l, 1) & r(l, 3) & r(l + 1, 0) & gettabs(l) & r(l, 2)
r(l + 1, 0) = ""
'Stop
For n = LBound(r) To UBound(r)
    If n >= l Then
        For i = 3 To 7
            If r(n, i) <> r(l, 5) Then r(n, i) = ""
        Next
    End If
Next

'r(l, 3) = r(l, 5)
r(l, 5) = ""


'Stop
'not implemented
'writeout (r(l, 0))
rlevelup = r
End Function

Private Sub writeout(s As String)

Dim fso As Object
Set fso = CreateObject("Scripting.FileSystemObject")
Dim oFile As Object
Set oFile = fso.CreateTextFile("c:/txt.txt")
oFile.WriteLine s
oFile.Close
Set fso = Nothing
Set oFile = Nothing

End Sub

将非规范化数据从excel导出到xml

2 个答案: