我有一张桌子,有点像历史性的桌子......所以我有这样的数据
idA numberMov FinalDate
1 10 20090209
2 14 20090304
1 12 20090304
3 54 20080508
4 42 20090510
... ... ....
我需要根据每个idA的最新finalDate检索numberMov,所以我使用了这个
select a.numberMov from (select idA, max(finalDate) maxDate from table1 group by idA) as b inner join table1 a on a.idA=b.idA and a.finalDate = b.maxDate
现在我有另外一个像这样的查询
select m fields from n tables where n5.numberMov in ("insert first query here")
我觉得有一个更好的解决方案,但想不出来,我真的不喜欢在那里有两个子查询。
有什么建议吗?
答案 0 :(得分:0)
您没有说哪个版本的SQL服务器,但这将在SQL 2005 +
中起作用;WITH rankCTE
AS
(
SELECT idA
,numberMov
,FinalDate
,ROW_NUMBER() OVER (PARTITION BY idA
ORDER BY FinalDate DESC
) AS rn
FROM table1
)
,latestCTE
AS
(
SELECT idA
,numberMov
,FinalDate
FROM rankCTE
WHERE rn = 1
)
SELECT m fields
FROM n tables
WHERE n5.numberMov IN (SELECT numberMov FROM latestCTE)
答案 1 :(得分:0)
没有足够的信息来自己测试,但这样的事情可能有用。
select m fields
from a inner join
(select numberMov,
max(FinalDate) as maxDate
from a
group by numberMov) b
on a.numberMov = b.numberMov
and a.FinalDate = b.maxDate inner join
n tables on a.numberMov = n.numberMov