我不知道为什么，但是下面的Python 3代码没有像我希望的那样在内部循环中运行tie(cell)函数（这样当循环板满时循环停止运行）
任何人都知道为什么？谢谢！
import random
cell = ['1', '2', '3', '4', '5', '6', '7', '8', '9']
def owin(cell):
if cell[0] == cell[1] == cell[2] == 'O' or cell[3] == cell[4] == cell[5] == 'O' or cell[6] == cell[7] == cell[8] == 'O' or cell[0] == cell[3] == cell[6] == 'O' or cell[1] == cell[4] == cell[7] == 'O' or cell[2] == cell[5] == cell[8]== 'O':
return True
else:
return False
def xwin(cell):
if cell[0] == cell[1] == cell[2] == 'X' or cell[3] == cell[4] == cell[5] == 'X' or cell[6] == cell[7] == cell[8] == 'X' or cell[0] == cell[3] == cell[6] == 'X' or cell[1] == cell[4] == cell[7] == 'X' or cell[2] == cell[5] == cell[8]== 'X':
return True
else:
return False
def tie(cell):
if cell[0] in ('O', 'X') and cell[1] in ('O', 'X') and cell[2] in ('O', 'X') and cell[3] in ('O', 'X') and cell[4] in ('O', 'X') and cell[5] in ('O', 'X') and cell[6] in ('O', 'X') and cell[7] in ('O', 'X') and cell[8] in ('O', 'X'):
return True
else:
return False
board = '\n\t ' + cell[0] + ' | ' + cell[1] + ' | ' + cell[2] + '\n\t-----------\n\t ' + cell[3] + ' | ' + cell[4] + ' | ' + cell[5] + '\n\t-----------\n\t ' + cell[6] + ' | ' + cell[7] + ' | ' + cell[8]
print('\tTIC TAC TOE\n\t\tBy Lewis Cornwall')
instructions = input('Would you like to read the instructions? (y/n)')
if instructions == 'y':
print('\nEach player takes turns to place a peice on the following grid:\n\n\t 1 | 2 | 3\n\t-----------\n\t 4 | 5 | 6\n\t-----------\n\t 7 | 8 | 9\n\nBy inputing a vaule when prompted. The first to 3 peices in a row wins.')
player1 = input('Enter player 1\'s name: ')
player2 = input('Enter player 2\'s name: ')
print(player1 + ', you are O and ' + player2 + ', you are X.')
nextPlayer = player1
while not owin(cell) and not xwin(cell) and not tie(cell):
print('This is the board:\n' + board)
if nextPlayer == player1:
move = input('\n' + player1 + ', select a number (1 - 9) to place your peice: ')
cell[int(move) - 1] = 'O'
board = '\n\t ' + cell[0] + ' | ' + cell[1] + ' | ' + cell[2] + '\n\t-----------\n\t ' + cell[3] + ' | ' + cell[4] + ' | ' + cell[5] + '\n\t-----------\n\t ' + cell[6] + ' | ' + cell[7] + ' | ' + cell[8]
nextPlayer = player2
else:
move = input('\n' + player2 + ', select a number (1 - 9) to place your peice: ')
cell[int(move) - 1] = 'X'
board = '\n\t ' + cell[0] + ' | ' + cell[1] + ' | ' + cell[2] + '\n\t-----------\n\t ' + cell[3] + ' | ' + cell[4] + ' | ' + cell[5] + '\n\t-----------\n\t ' + cell[6] + ' | ' + cell[7] + ' | ' + cell[8]
nextPlayer = player1
if owin(cell):
print('Well done, ' + player1 + ', you won!')
elif xwin(cell):
print('Well done, ' + player2 + ', you won!')
else:
print('Unfortunately, niether of you were able to win today.')
input('Press <enter> to quit.')
答案 0 :(得分：2)
在您编写的代码中，tie(cell)的唯一外观是这一个：
while not owin(cell) and not xwin(cell) and not tie(cell):
请注意，它是一个逻辑表达式，在几乎所有编程语言（包括Python）中都对逻辑表达式进行了优化，如下所示：
# here test_func() won't be invoked
if 1 or test_func():
pass
# here test_func() won't be invoked
if 0 and test_func():
pass
# here test_func() would be invoked
if 1 and test_func():
pass
# here test_func() would be invoked
if 0 or test_func():
pass
因此，tie(cell)未被调用的原因是owin(cell)或xwin(cell)返回true。
答案 1 :(得分：1)
替换函数tie（cell）中的Condition
if cell[0] in ('O', 'N') and cell[1] in ('O', 'N') and cell[2] in ('O', 'N') and cell[3] in ('O', 'N') and cell[4] in ('O', 'N') and cell[5] in ('O', 'N') and cell[6] in ('O', 'N') and cell[7] in ('O', 'N') and cell[8] in ('O', 'N'):
通过
if cell[0] in ('O', 'X') and cell[1] in ('O', 'X') and cell[2] in ('O', 'X') and cell[3] in ('O', 'X') and cell[4] in ('O', 'X') and cell[5] in ('O', 'X') and cell[6] in ('O', 'X') and cell[7] in ('O', 'X') and cell[8] in ('O', 'X'):
答案 2 :(得分：0)
条件应该是这样的：
while (not owin(cell) or not xwin(cell)) and not tie(cell):
答案 3 :(得分：0)
就像@PengyuCHEN所说的那样，
只有在其他2次检查后才会调用tie()函数。因此，如果重新排列该函数，您将看到问题已解决。所以，这应该有效：
while not tie(cell) and not (owin(cell) or xwin(cell)):
另外，虽然你没有要求，但我试图清理你的代码......
import random
instructions = '''
Each player takes turns to place a piece on the following grid:
1 | 2 | 3
-----------
4 | 5 | 6
-----------
7 | 8 | 9
By inputting a value when prompted. The first to 3 pieces in a row wins'''
form = '''
\t| %s | %s | %s |
\t-------------
\t| %s | %s | %s |
\t-------------
\t| %s | %s | %s |
'''
cell = ['1', '2', '3', '4', '5', '6', '7', '8', '9']
def win(cell, char):
return cell[0] == cell[1] == cell[2] == char or\
cell[3] == cell[4] == cell[5] == char or\
cell[6] == cell[7] == cell[8] == char or\
cell[0] == cell[3] == cell[6] == char or\
cell[1] == cell[4] == cell[7] == char or\
cell[2] == cell[5] == cell[8] == char
def tie(cell):
return all(c in ('O','X') for c in cell)
def get_input(player):
while True:
m = input('\n%s, select a number (1 - 9) to place your peice: ' % player)
try:
return int(m)
except BaseException:
print 'Invalid Input'
continue
board = form % tuple(cell)
print('\tTIC TAC TOE\n\t\tBy Lewis Cornwall')
instr = input('Would you like to read the instructions? (y/n) ')
if instr.startswith('y'):
print(instructions)
player1 = input('Enter player 1\'s name: ').strip()
player2 = input('Enter player 2\'s name: ').strip()
print(player1 + ', you are O and ' + player2 + ', you are X.')
nextPlayer = player1
while not tie(cell) and not (win(cell, 'O') or win(cell,"X")):
print('This is the board:\n' + board)
if nextPlayer == player1:
move = get_input(player1)
cell[move - 1] = 'O'
board = form % tuple(cell)
nextPlayer = player2
else:
move = get_input(player2)
cell[move - 1] = 'X'
board = form % tuple(cell)
nextPlayer = player1
if win(cell,"O"):
print('Well done, ' + player1 + ', you won!')
elif win(cell,"X"):
print('Well done, ' + player2 + ', you won!')
else:
print('Unfortunately, neither of you were able to win today.')
input('Press <enter> to quit.')