通过$ .ajax发出请求时从C#服务器代码中获取错误

时间:2013-03-12 08:05:38

标签: jquery asp.net ajax

我正在使用$.ajax向Asp.Net中的C#代码发送请求。每次我收到响应中的错误(在Firebug中检查),如:

{"Message":"Invalid JSON primitive: EmailAddress.","StackTrace":"   at System.Web.Script.Serialization.JavaScriptObjectDeserializer.DeserializePrimitiveObject()\r\n   at System.Web.Script.Serialization.JavaScriptObjectDeserializer.DeserializeInternal(Int32 depth)\r\n   at System.Web.Script.Serialization.JavaScriptObjectDeserializer.BasicDeserialize(String input, Int32 depthLimit, JavaScriptSerializer serializer)\r\n   at System.Web.Script.Serialization.JavaScriptSerializer.Deserialize(JavaScriptSerializer serializer, String input, Type type, Int32 depthLimit)\r\n   at System.Web.Script.Serialization.JavaScriptSerializer.Deserialize[T](String input)\r\n   at System.Web.Script.Services.RestHandler.GetRawParamsFromPostRequest(HttpContext context, JavaScriptSerializer serializer)\r\n   at System.Web.Script.Services.RestHandler.GetRawParams(WebServiceMethodData methodData, HttpContext context)\r\n   at System.Web.Script.Services.RestHandler.ExecuteWebServiceCall(HttpContext context, WebServiceMethodData methodData)","ExceptionType":"System.ArgumentException"}

如果我从data:{}删除了$.ajax参数,那就没关系了。我认为我向服务器发送数据的方式存在问题。

我的客户端代码是:   函数send_req(){

        $.ajax({
            url: "Demo.aspx/Demo_Method",
            contentType: "application/json; charset=UTF-8",
            type: "POST",
            data: {"EmailAddress": "abc@testmail.com"},
            success: function (response) {
                alert('Success' + response);
            }
        });
    }

Demo.aspx.cs页面代码是:

public partial class Demo : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)
    {

    }
    [WebMethod()]
    public static void Demo_Method(string EmailAddress)
    {
        //Some code....

    }
}

3 个答案:

答案 0 :(得分:2)

删除EmailAddress参数附近的引号:

$.ajax({
   url: "Demo.aspx/Demo_Method",
   contentType: "application/json; charset=UTF-8",
   type: "POST",
   data: {EmailAddress: "abc@testmail.com"},
          ^^^^^^^^^^^^

   success: function (response) {
         alert('Success' + response);
   }
});

答案 1 :(得分:0)

在我的调用中,我指定dataType: "json",并将整个data参数包装在引号中。

e.g。

    $.ajax({
        url: "Demo.aspx/Demo_Method",
        contentType: "application/json; charset=UTF-8",
        type: "POST",
        dataType: "json",
        data: "{'EmailAddress':'abc@testmail.com'}",
        success: function (response) {
            alert('Success' + response);
        }
    });

答案 2 :(得分:0)

尝试将数据作为字符串传递,而不是作为对象。

示例:

$.ajax({
        url: "Demo.aspx/Demo_Method",
        contentType: "application/json; charset=UTF-8",
        type: "POST",
        data:  '{"EmailAddress": "abc@testmail.com"}',
        success: function (response) {
            alert('Success' + response);
        }
    });