Question

我的客户有这个KTV小时规则所有退房时间超过20分钟将被视为额外的1小时。

以下示例代码：

  declare @dateStart as datetime, @dateEnd as datetime

  set @dateStart = cast('3/2/2013 8:00:00 PM' as datetime)
  set @dateEnd   = cast('3/2/2013 9:20:02 pm' as datetime)

  SELECT DATEDIFF(hour, @dateStart, @dateEnd)

上面的代码逻辑上返回1:20小时。在SQL Server中，它将返回1小时。如何调整此代码以返回2小时？

提前致谢。

Answer 1

使用此：

declare @dateStart as datetime, @dateEnd as datetime

set @dateStart = cast('3/2/2013 8:00:00 PM' as datetime)
set @dateEnd   = cast('3/2/2013 9:20:02 pm' as datetime)

SELECT CEILING(CAST( DATEDIFF(minute, @dateStart, @dateEnd)as float) / 60)

更多：CEILING

Answer 2

试试这个：

  declare @dateStart as datetime, @dateEnd as datetime

  set @dateStart = cast('3/2/2013 8:00:00 PM' as datetime)
  set @dateEnd   = cast('3/2/2013 9:20:02 pm' as datetime)

  SELECT DATEDIFF(hour, @dateStart, @dateEnd) 
+
case 
when datediff(minute,@dateStart, @dateEnd)%60>=20 then 1
else 0
end

更准确地说，你也可以在这里添加秒数。

Answer 3

将40分钟添加到已用时间，并截断为小时，如下所示：

  declare @dateStart as datetime, @dateEnd as datetime

  set @dateStart = cast('3/2/2013 8:00:00 PM' as datetime)
  set @dateEnd   = cast('3/2/2013 9:20:02 pm' as datetime)


  select Elapsed = datediff(hour, @dateStart, dateadd(minute,40,@dateEnd))

返回

Elapsed
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2

DATEDIFF舍入截止日期小时SQL Server

3 个答案: