我目前遇到此错误“解析数据时出错org.json.JSONException:的字符10处的输入结束”。我使用Chrome的Plugin Postman测试了我的PHP,服务器端似乎没问题。请查看以下代码并感谢您的帮助。
PHP代码:
public function login($alias, $password){
$user_info = $this->getUserFromDatabase($alias, $password);
if ($user_info != false){
$response["success"] = "true";
$response["user_id"] = $user_info["userID"];
$response["userFirstName"] = $user_info["userFirstName"];
$response["userRank"] = $user_info["userRank"];
echo json_encode($response);
}else{
$response["success"] = "false";
$response["error"] = "true";
echo json_encode($response);
}
}
public function getUserFromDatabase($android_alias, $android_password) {
$db_query = mysql_query("SELECT userID, userFirstName, userRank FROM capUserTable
WHERE userAlias = '$android_alias' AND userPassword = '$android_password'")
or die(mysql_error());
$query_results = mysql_fetch_assoc($db_query);
return $query_results;
}
邮差结果:
{
"success": "true",
"user_id": "1",
"userFirstName": "username",
"userRank": "99"
}
JAVA代码:
private InputStream inputStream = null;
private JSONObject jObject = null;
private String json = "";
public JSONparser() {
}
public JSONObject getJSONFromURL(String URL, List<NameValuePair> params){
try{
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(URL);
httpPost.setEntity(new UrlEncodedFormEntity(params));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
inputStream = httpEntity.getContent();
}catch(UnsupportedEncodingException e){
e.printStackTrace();
Log.e("UnsupportedEncodingException", "Unsupported Encoding Exception" + e.toString());
}catch(ClientProtocolException e){
e.printStackTrace();
}catch(IOException e){
e.printStackTrace();
}catch(Exception e){
e.printStackTrace();
}
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream, "iso-8859-1"), 10);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null){
sb.append(line + "\n");
}
inputStream.close();
json = sb.toString();
}catch(Exception e){
Log.e("Buffer Error", "Error converting result " + e.toString());
}
try{
jObject = new JSONObject(json); //this is where the problem occurs
}catch(JSONException e){
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
return jObject;
}
答案 0 :(得分:2)
您好我已经检查过您的回复是否有问题
String response = "{success\":\"true\",\"user_id\": \"1\",\"userFirstName\":\"username\", \"userRank\": \"99\"}";
它在json验证显示有效,但在成功键中没有“在启动所以它的创建json对象像
{"userFirstName":"username","user_id":"1","success\"":"true","userRank":"99"}
所以它无法从成功中获得价值
写下像
这样的内容String response = "{\"success\":\"true\",\"user_id\": \"1\",\"userFirstName\":\"username\", \"userRank\": \"99\"}";
它应该像这样解析
try {
JSONObject jobj = new JSONObject(response);
String succes = jobj.getString("success");
String userFirstName = jobj.getString("userFirstName");
String user_id = jobj.getString("user_id");
String userRank = jobj.getString("userRank");
String user_id = jobj.getString("user_id");
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
答案 1 :(得分:1)
// function get json from url
// by making HTTP POST or GET mehtod
public JSONObject makeHttpRequest(String url, String method,
List<NameValuePair> params) {
// Making HTTP request
try {
// check for request method
if(method == "POST"){
// request method is POST
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
httpPost.setEntity(new UrlEncodedFormEntity(params));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
}else if(method == "GET"){
// request method is GET
DefaultHttpClient httpClient = new DefaultHttpClient();
String paramString = URLEncodedUtils.format(params, "utf-8");
url += "?" + paramString;
HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
}
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// try parse the string to a JSON object
try {
Log.d("response string",json);
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON String
return jObj;
}
我希望它能帮助你