Question

我似乎无法修复这个小小的gremlin。

我有一个mySQL数据库，该表有一个描述字段。

我的客户已经使用了'字符很多，这打破了我从php生成的json。

我的脚本如下：

... database call...
$totalRows_rs_results = mysql_num_rows($rs_results);

            if($totalRows_rs_results >0){
                $myData = array();
                //echo('locations near this unitbase:');
                $myData['id'] = $row_rs_results['id_loc'];
                $myData['slug'] = $row_rs_results['slug_loc'];
                $myData['name'] = $row_rs_results['name_loc'];
                $myData['showname'] = $row_rs_results['showname_loc'];
                $myData['description'] = utf8_encode($row_rs_results['description_loc']);
                $myData['image'] = getDefaultLocationImage($database_reelfilm, $reelfilm, $row_rs_results['id_loc']);

                    $myAddress = ($row_rs_results['address_loc'].' '.$row_rs_results['postcode_loc']);
                    $myData['address'] = $myAddress;
                    $myData['maplat'] = $row_rs_results['maplat_loc'];
                    $myData['maplong'] = $row_rs_results['maplong_loc'];

                $myData['parking'] = $row_rs_results['parkinginfo_loc'];
                $myData['features'] = $row_rs_results['internalfeatures_loc'] . ' ' . $row_rs_results['externalfeatures_loc'];
                //$myData['categorys'] = getCategorys($database_reelfilm, $reelfilm, $row_rs_results['id_loc']);            
                $json[] = $myData;          
                $myJSON = json_encode($json);
                return $myJSON;
            };


<span class='showOnMap' data-location='<?php echo makeJSON($database_reelfilm, $reelfilm, 'location', $row_rs_locations['id_loc']);?>' '>
<img src="/images/Icons/map-icon.png" width="32" height="32">
</span>

输出的json很好，直到我用前面提到的'字符来记录。

如果我从记录中删除有问题的'字符，我得到正确的输出：

<span class="showOnMap" data-related="" data-categorys="" data-location="[{"id":"29","slug":"the-butts","name":"The Butts","showname":"1","description":"Controllable period street location. Looks like an A road or a bus route. Surrounding houses are Georgian or early Victorian.","image":"The Butts 3.jpg","address":"Brentford\r\nLondon TW8 8BQ","maplat":"51.4847373","maplong":"-0.30824250000000575","parking":"","features":" "}]">
<img width="32" height="32" src="/images/Icons/map-icon.png">
</span>

使用'character：

生成的数据输出

<span class="showOnMap" data-related="" data-categorys="" "}]'="" 8bq","maplat":"51.4847373","maplong":"-0.30824250000000575","parking":"","features":"="" tw8="" 3.jpg","address":"brentford\r\nlondon="" butts="" victorian.","image":"the="" early="" georgian="" are="" houses="" surrounding="" route.="" bus="" a="" or="" road="" a'="" data-location="[{"id":"29","slug":"the-butts","name":"The Butts","showname":"1","description":"Controllable period street location. Looks like an ">
<img width="32" height="32" src="/images/Icons/map-icon.png">
</span>

现在告诉我的客户通过并删除所有违规的字符（超过1000条记录），这对我来说似乎非常不专业。

我试过htmlspecialchars（），utf8_encode（）试图解决问题，不确定我需要使用哪一个，是否有人能指出我正确的方向？

Answer 1

您使用嵌套引号会破坏它。试试这个：

<span class='showOnMap' data-location='<?php echo makeJSON($database_reelfilm, $reelfilm, "location", $row_rs_locations["id_loc"]);?>'>

通过在单引号中嵌套单引号，您可以结束字符串...在单引号和双引号之间切换将正确地将它们包含在完整字符串中。

Answer 2

您应该使用htmlentities()对值进行实体编码，例如：

<span class='showOnMap' data-location='<?php echo htmlentities(makeJSON($database_reelfilm, $reelfilm, 'location', $row_rs_locations['id_loc']));?>'>

Answer 3

有很多方法可以解决

使用addslases函数或使用htmlspecialchars函数

$myData['description']=htmlspecialchars(utf8_encode($row_rs_results['description_loc'],ENT_QUOTES));

                     OR
    $myData['description']=addslashes($myData['description']);

'字符正在破坏我用php生成的json输出

3 个答案: