Question

我有一个纬度\经度点数的DB。我试图得到DISTINCT圆形结果按距离排序。我的查询如下：

SELECT
   DISTINCT ROUND(`lat`,2), ROUND(`lon`,2),
   ( 3959 * acos( cos( radians(LAT_HERE) )
          * cos( radians( `lat` ) )
          * cos( radians( `lon` ) - radians(LONG_HERE) )
          + sin( radians(LAT_HERE) )
          * sin( radians( `lat` ) ) ) ) AS distance
FROM `user_data`
HAVING distance <= 99
ORDER BY distance
LIMIT 100

在该回合之前，该运行正在运行。例如（29.333,29.334），（29.331,29.332）将显示两次。

Answer 1

尝试使用GROUP BY

    SELECT  ROUND(`lat`,2), ROUND(`lon`,2),
                   ( 3959 * acos( cos( radians(LAT_HERE) )
                   * cos( radians( `lat` ) )
                   * cos( radians( `lon` ) - radians(LONG_HERE) )
                   + sin( radians(LAT_HERE) )
                   * sin( radians( `lat` ) ) ) ) AS distance
                FROM `user_data`
                GROUP BY ROUND(`lat`,2) 
                HAVING distance <= 99
                ORDER BY distance
                LIMIT 100

Answer 2

其实你不对。 DISTINCT在先前评估的结果上运行。运行例如：

select distinct round(a,2), round(b,2) 
from ((select 29.333 as a,29.334 as b) union (select 29.331,29.332)) t3;

结果是：

+------------+------------+
| round(a,2) | round(b,2) |
+------------+------------+
|      29.33 |      29.33 |
+------------+------------+

MySQL中有不同的ROUNDED结果

2 个答案: