检查last.fm中是否存在key返回的json

时间:2013-03-11 16:04:24

标签: iphone ios objective-c xcode last.fm

我正在编写一个使用last.fm网络服务搜索相册的iOS应用。以下代码将返回的json转换为NSArray:

results = (NSArray *)[[[json valueForKey:@"results"] valueForKey:@"albummatches"] valueForKey:@"album"];

当搜索词返回结果时,此方法正常,但是当没有返回结果时应用程序崩溃。这是因为当没有找到结果时,json中不存在关键的“专辑”。

如何让我的应用程序检查json中是否存在“album”键?

编辑:当没有结果时返回示例json。搜索字符串是'asdfgasdfg'。请注意相册匹配下的字符返回。

2013-03-12 14:08:00.889 MyMusicLibrary[387:1a03] {
results =     {
    "@attr" =         {
        for = asdfgasdfg;
    };
    albummatches = "\n";
    "opensearch:Query" =         {
        "#text" = "";
        role = request;
        searchTerms = asdfgasdfg;
        startPage = 1;
    };
    "opensearch:itemsPerPage" = 50;
    "opensearch:startIndex" = 0;
    "opensearch:totalResults" = 0;
};
}

编辑2:返回结果时的样本json:

2013-03-12 14:19:42.769 MyMusicLibrary[880:1a03] {
results =     {
    "@attr" =         {
        for = coldplay;
    };
    albummatches =         {
        album =             (
                            {
                artist = Coldplay;
                id = 1416655;
                image =                     (
                                            {
                        "#text" = "http://userserve-ak.last.fm/serve/34s/85845017.png";
                        size = small;
                    },
                                            {
                        "#text" = "http://userserve-ak.last.fm/serve/64s/85845017.png";
                        size = medium;
                    },
                                            {
                        "#text" = "http://userserve-ak.last.fm/serve/126/85845017.png";
                        size = large;
                    },
                                            {
                        "#text" = "http://userserve-ak.last.fm/serve/300x300/85845017.png";
                        size = extralarge;
                    }
                );
                mbid = "c67be398-9417-4c22-bc13-d6158029ae21";
                name = "A Rush of Blood to the Head";
                streamable = 1;
                url = "http://www.last.fm/music/Coldplay/A+Rush+of+Blood+to+the+Head";
            },
                            {
                artist = Coldplay;
                id = 1984;
                image =                     (
                                            {
                        "#text" = "http://userserve-ak.last.fm/serve/34s/87203265.png";
                        size = small;
                    },
                                            {
                        "#text" = "http://userserve-ak.last.fm/serve/64s/87203265.png";
                        size = medium;
                    },
                                            {
                        "#text" = "http://userserve-ak.last.fm/serve/126/87203265.png";
                        size = large;
                    },
                                            {
                        "#text" = "http://userserve-ak.last.fm/serve/300x300/87203265.png";
                        size = extralarge;
                    }
                );
                mbid = "8e602038-c0f2-3c2d-9068-a1a3daca493d";
                name = Parachutes;
                streamable = 1;
                url = "http://www.last.fm/music/Coldplay/Parachutes";
            }
        );
    };
    "opensearch:Query" =         {
        "#text" = "";
        role = request;
        searchTerms = coldplay;
        startPage = 1;
    };
    "opensearch:itemsPerPage" = 2;
    "opensearch:startIndex" = 0;
    "opensearch:totalResults" = 375;
};
}

3 个答案:

答案 0 :(得分:1)

有两种方法可以解决这个问题

  1. 假设"opensearch:totalResults"实际上是正确的结果计数,那么您可以使用此值来确定您是否有结果,然后使用

    NSArray *results = nil;
    
    if ([[json valueForKeyPath:@"results.opensearch:totalResults"] intValue] > 0) {
      results = [json valueForKeyPath:@"results.albummatches.album"];
    }
    
  2. 在处理之前检查您是否有字符串或数组

    id albummatches = [json valueForKeyPath:@"results.albummatches"];
    
    // is this a dictionary or a string?
    // You can either ask if it implements the interface or ask what class it is. I prefer the first
    BOOL isDictionary = [albummatches respondsToSelector:@selector(objectForKey:)];
    
    // or
    BOOL isDictionary = [albummatches isKindOfClass:[NSDictionary class]];
    
    if (isDictionary) {
      results = [albummatches objectForKey:@"album"];
    }
    

答案 1 :(得分:0)

检查:

if([[json[@"result"][@"albummatches"] allKeys] containsObject:@"album"]==YES){

    //do your work here
}

答案 2 :(得分:0)

之前有人发布了一个非常好的答案,但后来被删除了。虽然它有很多帮助,但我稍微修改了它以获得下面的代码,现在可以使用了。

            NSDictionary *resultsDict = [json valueForKey:@"results"];
        if (resultsDict != nil) {
            //Checks to see if any results are returned
            NSDictionary *albumMatchesDict = [resultsDict valueForKey:@"albummatches"];
            NSString *albumMatchesString = [resultsDict valueForKey:@"albummatches"];
            NSCharacterSet *set = [NSCharacterSet whitespaceCharacterSet];
            albumMatchesString = [[albumMatchesString description] stringByTrimmingCharactersInSet:[NSCharacterSet newlineCharacterSet]];

            if ([[albumMatchesString stringByTrimmingCharactersInSet:set] length] != 0) {
                results = (NSArray *) [albumMatchesDict valueForKey:@"album"];
            }
        }