我有一个mysql查询,目前按月汇总数据:
$sql = SELECT SellerName,
SUM(IF(ReportMonth = 201201, 1,0)) AS Jan,
SUM(IF(ReportMonth = 201202, 1,0)) AS Feb,
SUM(IF(ReportMonth = 201203, 1,0)) AS Mar,
SUM(IF(ReportMonth = 201204, 1,0)) AS Apr,
SUM(IF(ReportMonth = 201205, 1,0)) AS May,
SUM(IF(ReportMonth = 201206, 1,0)) AS Jun,
SUM(IF(ReportMonth = 201207, 1,0)) AS Jul,
SUM(IF(ReportMonth = 201208, 1,0)) AS Aug,
SUM(IF(ReportMonth = 201209, 1,0)) AS Sep,
SUM(IF(ReportMonth = 201210, 1,0)) AS Oct,
SUM(IF(ReportMonth = 201211, 1,0)) AS Nov,
COUNT(*) AS YTD
FROM onlineDATA
WHERE BuyerZipCode IN ($zips_query)
GROUP BY SellerName
这很有效。
但是,我需要调整它以允许用户输入月份 - 即用户将选择开始和结束月份。
我可以将datepicker数据格式化为现有的yyyymm格式 - 但是我如何在PHP中制定查询以调整可变月份并计算多年(例如2012年8月至2013年2月)?
谢谢!
答案 0 :(得分:0)
您的方法只能使用一年;否则,如果您不希望将多年的月份组合在一起,则需要其他列。您还应该使用date
函数而不是检查整数值(您不应该将日期存储为int)。
如果需要动态方法,则需要在PHP端进行动态查询准备(获取开始/结束日期并生成SQL)。
这可能是您正在寻找的解决方案:
<?php
$startDate = '201201';
$endDate = '201303';
$formattedStartDate = strtotime( SUBSTR($startDate, 0, 4) . '-' . SUBSTR($startDate, -2, 2) . '-01' );
$formattedEndDate = strtotime( SUBSTR($endDate, 0, 4) . '-' . SUBSTR($endDate, -2, 2) . '-01' );
$sql = "SELECT SellerName, \n";
while ($formattedStartDate <= $formattedEndDate) {
$sql .= 'SUM(IF(LEFT(ReportMonth, 4) = ' . date('Y', $formattedStartDate) . ' AND RIGHT(ReportMonth, 2) = ' . date('m', $formattedStartDate) . ")) AS '" . date('M Y', $formattedStartDate);
if($formattedStartDate <> $formattedEndDate) {
$sql .= "', \n";
}
else {
$sql .= "'\n";
}
$formattedStartDate = strtotime('+1 month', $formattedStartDate);
}
$sql .= 'COUNT(*) AS YTD
FROM onlineDATA
WHERE BuyerZipCode IN ($zips_query)
GROUP BY SellerName';
echo $sql;
<强>结果强>
SELECT SellerName, SUM(IF(LEFT(ReportMonth, 4) = 2012 AND RIGHT(ReportMonth, 2) = 01)) AS 'Jan 2012', SUM(IF(LEFT(ReportMonth, 4) = 2012 AND RIGHT(ReportMonth, 2) = 02)) AS 'Feb 2012', SUM(IF(LEFT(ReportMonth, 4) = 2012 AND RIGHT(ReportMonth, 2) = 03)) AS 'Mar 2012', SUM(IF(LEFT(ReportMonth, 4) = 2012 AND RIGHT(ReportMonth, 2) = 04)) AS 'Apr 2012', SUM(IF(LEFT(ReportMonth, 4) = 2012 AND RIGHT(ReportMonth, 2) = 05)) AS 'May 2012', SUM(IF(LEFT(ReportMonth, 4) = 2012 AND RIGHT(ReportMonth, 2) = 06)) AS 'Jun 2012', SUM(IF(LEFT(ReportMonth, 4) = 2012 AND RIGHT(ReportMonth, 2) = 07)) AS 'Jul 2012', SUM(IF(LEFT(ReportMonth, 4) = 2012 AND RIGHT(ReportMonth, 2) = 08)) AS 'Aug 2012', SUM(IF(LEFT(ReportMonth, 4) = 2012 AND RIGHT(ReportMonth, 2) = 09)) AS 'Sep 2012', SUM(IF(LEFT(ReportMonth, 4) = 2012 AND RIGHT(ReportMonth, 2) = 10)) AS 'Oct 2012', SUM(IF(LEFT(ReportMonth, 4) = 2012 AND RIGHT(ReportMonth, 2) = 11)) AS 'Nov 2012', SUM(IF(LEFT(ReportMonth, 4) = 2012 AND RIGHT(ReportMonth, 2) = 12)) AS 'Dec 2012', SUM(IF(LEFT(ReportMonth, 4) = 2013 AND RIGHT(ReportMonth, 2) = 01)) AS 'Jan 2013', SUM(IF(LEFT(ReportMonth, 4) = 2013 AND RIGHT(ReportMonth, 2) = 02)) AS 'Feb 2013', SUM(IF(LEFT(ReportMonth, 4) = 2013 AND RIGHT(ReportMonth, 2) = 03)) AS 'Mar 2013' COUNT(*) AS YTD FROM onlineDATA WHERE BuyerZipCode IN ($zips_query) GROUP BY SellerName
答案 1 :(得分:0)
你应该能够做到这一点,我确信这样的事情是一个开始:
SELECT SUM(ReportMonth) FROM SellerName
WHERE BuyerZipCode IN ($zips_query)
AND ReportMonth > '$start_date'
AND ReportMonth < DATE_ADD('$start_date', INTERVAL 1 YEAR)
GROUP BY ReportMonth
e.g。
SELECT SUM(ReportMonth) FROM SellerName
WHERE BuyerZipCode IN (1,2,3,4,5,6)
AND ReportMonth > '2013-01-01'
AND ReportMonth < DATE_ADD('2013-01-01', INTERVAL 1 YEAR)
GROUP BY ReportMonth