Question

我在GSON的JSON解析中遇到问题

我的JSONERESPONSE是

    {"services":[{"service":{"name":"asd","id":"1"}},
    {"service":{"name":"asdf","id":"2"}},
    {"service":{"name":"asdfg","id":"3"}}]}

如何解析此回复？

表示我在创建上述响应类时遇到问题我创建了服务类，但我对如何创建服务类感到困惑。

public class services {

@SerializedName("service")
ArrayList<service> list;

public services(){
    System.out.println("services constructor stuff");
    list= new ArrayList<service>();
}

/**
 * @return the list
 */
public ArrayList<service> getList() {
    return list;
}

/**
 * @param list the list to set
 */
public void setList(ArrayList<service> list) {
    this.list = list;
}

}

but getting 0 in getList();

注意：我无法更改响应，因此不建议

谢谢

Answer 1

Services.java

public class Services {

    private List<Service> services;

    public List<Service> getServiceList() {
        return services;
    }

    public void setServiceList(List<Service> services) {
        this.services = services;
    }
}

Service.java

public class Service {

    private int id;
    private String name;

    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }
}

你的json解析逻辑就在这里：

Gson gson = new Gson();
String s = "{\"services\":[{\"service\":{\"name\":\"asd\",\"id\":\"1\"}},{\"service\":{\"name\":\"asdf\",\"id\":\"2\"}},{\"service\":{\"name\":\"asdfg\",\"id\":\"3\"}}]}";
Services services = gson.fromJson(s, Services.class);

基本上，json字符串不是简单的json数组格式，它实际上是json对象中的json数组。所以它暗示你需要两个Class，一个代表json数组中的每个项目 - Service.java，另一个代表一个包含项目列表的包装器。

Answer 2

好的，我们需要创建一个中间层类来使其正确。的 Services.java

public class Services { private ArrayList<ServiceWrapper> services = new ArrayList<ServiceWrapper>(); public ArrayList<ServiceWrapper> getServices() { return services; } public void setServices(ArrayList<ServiceWrapper> services) { this.services = services; } }

<强> ServiceWrapper.java

public class ServiceWrapper { private Service service; public Service getService() { return service; } public void setService(Service service) { this.service = service; } }

<强> Service.java

public class Service { private int id; private String name; public int getId() { return id; } public void setId(int id) { this.id = id; } public String getName() { return name; } public void setName(String name) { this.name = name; } }

以下是测试代码

Gson gson = new Gson(); String s = "{\"services\":[{\"service\":{\"name\":\"asd\",\"id\":\"1\"}},{\"service\":{\"name\":\"asdf\",\"id\":\"2\"}},{\"service\":{\"name\":\"asdfg\",\"id\":\"3\"}}]}"; Services services = gson.fromJson(s, Services.class); for(ServiceWrapper serviceWrapper : services.getServices()){ System.out.println(serviceWrapper.getService().getId()); System.out.println(serviceWrapper.getService().getName()); }

GSON在JSON解析中的问题

2 个答案: