Question

我被困在一个查询上，

在哪里我有52周的数据，我可以根据sysdate安排获取周数并与数据周数比较。现在我要做的是，如果当前周数为10，我想按降序安排所有周，例如取决于sysdate周数周10，周9，周8 .........周11，

使用此查询

select "Weekly","Quarter","SALES","Monthly",week_number from fiscal_calendar
where week_number <= TO_CHAR(TO_DATE(sysdate,'DD-mon-YYYY'),'iw') 
order by  week_number desc;

我能够将数据排序到第1周，但我希望继续这样的序列，比如在第11周结束所以我做错了什么请建议

Answer 1

如果我理解正确，你可以尝试

SELECT * FROM
(SELECT "Weekly","Quarter","SALES","Monthly",week_number FROM fiscal_calendar
  WHERE week_number <= TO_NUMBER(TO_CHAR(SYSDATE,'IW')) 
  ORDER BY  week_number desc) t1
UNION ALL
SELECT * FROM 
(SELECT "Weekly","Quarter","SALES","Monthly",week_number FROM fiscal_calendar
  WHERE week_number > TO_NUMBER(TO_CHAR(SYSDATE,'IW'))
  ORDER BY  week_number) t2

以下是简化SQLFiddle example

Answer 2

我们可以在order by子句中使用case()（或decode()} ...

order by case 
           when week_number = to_number(to_char(sysdate, 'WW')) then 1
           when week_number < to_number(to_char(sysdate, 'WW')) then 2
           when week_number > to_number(to_char(sysdate, 'WW')) then 3
         end ASC
         , week_number DESC

根据当前系统日期对数据进行排序

2 个答案: