Question

我正试图使用以下内容从weather site刮取温度：

    import urllib2
from BeautifulSoup import BeautifulSoup

f = open('airport_temp.tsv', 'w')

f.write("Location" + "\t" + "High Temp (F)" + "\t" + "Low Temp (F)" + "\t" + "Mean Humidity" + "\n" )

eventually parse from http://www.wunderground.com/history/airport/\w{4}/2012/\d{2}/1/DailyHistory.html

for x in range(10):
    locationstamp = "Location " + str(x)
    print "Getting data for " + locationstamp
    url = 'http://www.wunderground.com/history/airport/KAPA/2013/3/1/DailyHistory.html'

    page = urllib2.urlopen(url)
    soup = BeautifulSoup(page)

    location = soup.findAll('h1').text
    locsent = location.split()
    loc = str(locsent[3,6]) 

    hightemp = soup.findAll('nobr')[6].text
    htemp = hightemp.split()
    ht = str(htemp[1]) 

    lowtemp = soup.findAll('nobr')[10].text
    ltemp = lowtemp.split()
    lt = str(ltemp[1]) 

    avghum = soup.findAll('td')[23].text

    f.write(loc + "\t|" + ht + "\t|" + lt + "\t|" + avghum + "\n" )

f.close()

不幸的是，我收到错误消息：

Getting data for Location 0
Traceback (most recent call last):
  File "airportweather.py", line 18, in <module>
    location = soup.findAll('H1').text
AttributeError: 'list' object has no attribute 'text'

我查看过BS和Python文档，但我仍然很绿，所以我无法弄明白。请帮助这个新手！

Answer 1

.findAll()方法返回匹配的列表。如果您想要一个结果，请改用.find()方法。或者，选择一个特定元素，如代码的其余部分，或循环结果：

location = soup.find('h1').text

或

locations = [el.text for el in soup.findAll('h1')]

或

location = soup.findAll('h1')[2].text

Answer 2

这很简单。 findAll会返回列表，因此如果您确定只有一个有趣的元素，那么：soup.findAll('H1')[0].text应该可以使用

beautifulsoup“列表对象没有属性”错误

2 个答案: