* 它说未定义的索引和5次fout意味着什么错误但如果我点击了正确它也说fout 5次。 *
该节目是一个小问题,在一个问题之后重复一个问题,如果它是错的,他说fout如果它是正确的,它说juist。
<!DOCTYPE html>
<html>
<head>
<title>Talenquiz2</title>
</head>
<body>
<?php
session_start();
if(isset($_SESSION["vraagnr"]))
{
if (isset($_GET["controleer"]))
{
// The browser said that these 4 lines have an undefined index
$vraag = $_GET["vraag"];
$juistantwoord = $_GET["juistantwoord"];
$foutantwoord1 = $_GET["foutantwoord1"];
$foutantwoord2 = $_GET["foutantwoord2"];
$con = mysql_connect("localhost","root","");
mysql_select_db("dbproject", $con);
$result = mysql_query("SELECT * FROM tblquizvragen");
while($row = mysql_fetch_array($result))
{
// Here is the program checking wich checkbox is checked and which is not
if (isset($_GET['ok']) && !isset($_GET['nee1']) && !isset($_GET['nee2']))
{
echo "Dit is Correct.";
}
else
{
echo "Dit is fout.";
}
}
mysql_close($con);
echo "\n<hr />\n";
}
}
else
{
$_SESSION["vraagnr"]=1;
}
$con = mysql_connect("localhost","root","");
mysql_select_db("dbproject", $con);
$result = mysql_query("SELECT * FROM tblquizvragen WHERE id='". $_SESSION["vraagnr"] . "';");
$row = mysql_fetch_array($result);
$vraag = $row['vraag'];
$juistantwoord = $row['juistantwoord'];
$foutantwoord1 = $row['foutantwoord1'];
$foutantwoord2 = $row['foutantwoord2'];
mysql_close($con);
?>
<form>
<p><?php echo $vraag; ?></p>
<input type="checkbox" name="juistantwoord" value="ok" /><?php echo $juistantwoord; ?><br />
<input type="checkbox" name="foutantwoord1" value="nee1" /><?php echo $foutantwoord1; ?><br />
<input type="checkbox" name="foutantwoord2" value="nee2" /><?php echo $foutantwoord2; ?><br />
<input type="submit" value="Controleer je antwoord" name="controleer" />
</form>
</body>
</html>
答案 0 :(得分:1)
您应该在任何输出之前将session_start();
放在文档的开头
所以你会把它作为:
<?php session_start(); ?>
<!DOCTYPE html>
<html>
<head>
<title>Talenquiz2</title>
</head>
<body>
<?php
if(isset($_SESSION["vraagnr"]))
{
// etc..
答案 1 :(得分:0)
如果表单是通过帖子提交的,请尝试$_POST
而不是$_GET