这是我的xml示例: -
<products>
<product_id value="1">
<tab_id value="351">
<date value="30-09-1989" />
</tab_id>
</product_id>
<product_id value="2">
<tab_id value="352">
<date value="03-03-1990" />
</tab_id>
</product_id>
</products>
这是我试过的: -
<html>
<head>
<title>Less,Grater,Equal</title>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<script>
var xml;
$.get(
"xml_Converted.xml",
null,
function (data) {
xml = data;
},
"xml"
);
function get_list()
{
var ename = $('#select').val();
var xPath = '//*["' + ename + '" = ' +
' //date/@value' + '"]/../../@value';
var iterator = xml.evaluate(xPath, xml.documentElement, null,
XPathResult.UNORDERED_NODE_ITERATOR_TYPE, null);
var thisNode = iterator.iterateNext();
var str = '';
while (thisNode) {
if (str) {
str += ', ';
}
str += thisNode.textContent;
thisNode = iterator.iterateNext();
}
$("#result").text(str);
}
</script>
<body>
<input type="text" id="select">
<input type="button" value="search">
<div id="result"></div>
</body>
</head>
</html>
这里我想o / p如果用户在文本框中输入日期然后在xml树上匹配它的soud返回xml树的第一个元素attribut值(product_id值)o / p是1
答案 0 :(得分:0)
更改此内容:
var iterator = xml.evaluate(xPath, xml.documentElement, null,
XPathResult.UNORDERED_NODE_ITERATOR_TYPE, null);
var thisNode = iterator.iterateNext();
var str = '';
while (thisNode) {
if (str) {
str += ', ';
}
str += thisNode.textContent;
thisNode = iterator.iterateNext();
}
到此:
var node = xml.evaluate(xPath, xml.documentElement, null,
XPathResult.FIRST_ORDERED_NODE_TYPE, null);
var str = node.singleNodeValue ? node.singleNodeValue.textContent : '';
应该这样做。