从三个SELECT语句中插入表

时间:2013-03-08 15:02:42

标签: sql insert

第一个选择填充countOfActivePlans:

SELECT COUNT(DISTINCT a.txtprogram) AS countOfActivePlans, c.txtLevel1
FROM tblOfferings a, tblClaims b, tblRetailers c
WHERE a.ysnActive=1 
      AND c.intRetailer=b.intRetailer 
      AND c.intRetailer=a.intRetailer
GROUP BY c.txtLevel1
ORDER BY c.txtLevel1

第二个选择填充plansWithActivity:

SELECT COUNT(DISTINCT a.txtProgram) AS plansWithActivity,   c.txtLevel1
FROM tblClaims a, tblOfferings b, tblRetailers 
WHERE a.intOffering=b.intOffering 
      AND c.intRetailer=a.intRetailer 
      AND c.intRetailer=b.intRetailer
GROUP BY c.txtlevel1
ORDER BY c.txtLevel1

第三个填充Approved,Denied和sumOfcurPaid:

SELECT COUNT(a.dblTransaction) AS invoicesSubmitted, SUM(curPaid) AS sumOfcurPaid, b.txtLevel1, 
       CASE WHEN a.intTransCode=0 THEN 'Denied' 
            WHEN a.intTransCode=1 THEN 'Approved' 
            ELSE 'Reissued' 
       END AS txtLabel
FROM tblClaims a, tblRetailers b, tbLTransCode c
WHERE a.intRetailer=b.intRetailer 
      AND a.intTransCode=c.intTransCode
GROUP BY b.txtLevel1, 
       CASE WHEN a.intTransCode=0 THEN 'Denied' 
            WHEN a.intTransCode=1 THEN 'Approved' 
            ELSE 'Reissued' 
       END
ORDER BY b.txtLevel1 asc

表格如下。

如何制作填充表格的INSERT

Area countOfActivePlans plansWithActivity   approved    denied  sumOfCurPaid
-----------------------------------------------------------------------------
CE   237                230                 89898       11438   1238152.858
NE   189                178                 54159       5667    1665176.757
SE   177                165                 58675       5873    1406241.758
SW   118                111                 32450       6934    1329101.503
WE   152                145                 40266       3473    529956.6875

1 个答案:

答案 0 :(得分:2)

INSERT INTO
  MyTable (Area,countOfActivePlans,plansWithActivity,approved,denied,sumOfCurPaid)
SELECT
  f1.Area, f2.countOfActivePlans, f3.plansWithActivity, f4.Approved, f4.Denied, f4.sumOfcurPaid,
FROM
  (SELECT [THAT GETS THE AREA])           AS f1
CROSS JOIN
  (SELECT COUNT(DISTINCT a.txtprogram) AS countOfActivePlans, c.txtLevel1
    FROM tblOfferings a, tblClaims b, tblRetailers c
    WHERE a.ysnActive=1 
      AND c.intRetailer=b.intRetailer 
      AND c.intRetailer=a.intRetailer
    GROUP BY c.txtLevel1
    ORDER BY c.txtLevel1 )           AS f2
CROSS JOIN
  (SELECT COUNT(DISTINCT a.txtProgram) AS plansWithActivity,   c.txtLevel1
    FROM tblClaims a, tblOfferings b, tblRetailers c
    WHERE a.intOffering=b.intOffering 
      AND c.intRetailer=a.intRetailer 
      AND c.intRetailer=b.intRetailer
    GROUP BY c.txtlevel1
    ORDER BY c.txtLevel1) AS f3
CROSS JOIN
  (SELECT COUNT(a.dblTransaction) AS invoicesSubmitted, SUM(curPaid) AS sumOfcurPaid, b.txtLevel1, 
   CASE WHEN a.intTransCode=0 THEN 'Denied' 
        WHEN a.intTransCode=1 THEN 'Approved' 
        ELSE 'Reissued' 
   END AS txtLabel
   FROM tblClaims a, tblRetailers b, tbLTransCode c
   WHERE a.intRetailer=b.intRetailer 
    AND a.intTransCode=c.intTransCode
   GROUP BY b.txtLevel1, 
   CASE WHEN a.intTransCode=0 THEN 'Denied' 
        WHEN a.intTransCode=1 THEN 'Approved' 
        ELSE 'Reissued' 
   END
   ORDER BY b.txtLevel1 asc)           AS f4

我认为这样可以,但我已经将基本想法包含在下面,只是因为我上面的代码错了。

INSERT INTO
  MyTable (Col1,Col2,Col3,Col4,Col5,Col6)
SELECT
  f1.col1, f2.col2, f3.col3, f4.col4, f4.col5, f4.col6
FROM
  (SELECT Col1 FROM QUERYWITHAREA)    AS f1
CROSS JOIN
  (SELECT Col2 FROM QUERY1)           AS f2
CROSS JOIN
  (SELECT Col3 FROM QUERY2)           AS f3
CROSS JOIN
  (SELECT Col4,Col5,Col6 FROM QUERY3) AS f4

希望这会有所帮助,对不起,如果第一个例子并不完美,那么它就是一个帮助你的指南。老实说,我很想把你问题中的每个查询都放到一个函数中,然后用上面的样式调用每个函数。

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