SQL将多个行组合成一个具有多个列的行

时间:2013-03-08 08:57:14

标签: sql sql-server sql-server-2008-r2

我的查询结果中有多行:

例如,表“地址”:

Street | Number | City
----------------------
A1     | A2     | A3
B1     | B2     | B3

我真正想要的是:

Address1_Street | Address1_Number | Address1_City | Address2_Street | Address2_Number | Address2_City
------------------------------------------------------------------------------------------------------
A1              | A2              | A3            | B1              | B2              | B3

任何知道如何实现这一目标的人?

我现在已经设法达到这一点(对不起使用其他专栏,上面的一个是一个例子,但我猜你会明白这一点):

select distinct
    a.ID,
    a.Name, 
    ca1.NameLine1 as Address1_NameLine1, 
    ca2.NameLine1 as Address2_NameLine1
from 
    dbo.Accounts a, 
    dbo.Addresses ca1,
    dbo.Addresses ca2
where 
        (a.ID = ca1.AccountID AND a.ID = ca2.AccountID)
    AND (a.Name = 'TEST')
    AND (ca1.ID <> ca2.ID)

但我仍然得到2行......其中Address1用Address2切换。谁知道如何只得到一个?谢谢!

2 个答案:

答案 0 :(得分:5)

尝试:

select ID,
       max(Name) Name,
       max(case when rn=1 then NameLine1 end) Address1_NameLine1,
       max(case when rn=2 then NameLine1 end) Address1_NameLine2
from
(select a.ID,
        a.Name, 
        ca.NameLine1,
        rank() over (partition by a.ID order by ca.ID) rn
 from dbo.Accounts a 
 join dbo.Addresses ca on a.ID = ca.AccountID
 where a.Name = 'TEST') sq
group by ID

答案 1 :(得分:1)

select address1.* ,address2.* from
Address address1 inner join on Address address2
on address1.userid=address2.userid

您可以根据数据选择内部或左侧连接。