Question

我有以下文件清单：

List<DocumentInfo> list1 = new List<DocumentInfo>()
{
   new DocumentInfo { Name = "Customer1", DocCount = 5 },
   new DocumentInfo { Name = "Customer1", DocCount = 10 },
   new DocumentInfo { Name = "Customer1", DocCount = 5 },
   new DocumentInfo { Name = "Customer2", DocCount = 4 },
   new DocumentInfo { Name = "Customer2", DocCount = 6 },
   new DocumentInfo { Name = "Customer3", DocCount = 3 }
};

如何使用Linq基于'名称'和'DocCount'的总和对上面的列表进行分组并存储在另一个列表中？我想要以下内容：

Name = "Customer1", DocCount = 20
Name = "Customer2", DocCount = 10
Name = "Customer3", DocCount = 3

Answer 1

var results = list1.GroupBy(i => i.Name)
                   .Select(g => new
                                {
                                    Name = g.Key,
                                    DocCount = g.Sum(i => i.DocCount)
                                });

Answer 2

var list2 = list1.GroupBy(x => x.Name).Select(g => new DocumentInfo()
                                      {
                                          Name = g.Key,
                                          DocCount = g.Sum(x => x.DocCount)
                                      });

Answer 3

试试这个：

list1.GroupBy(di => di.Name).Select(g => new DocumentInfo {Name = g.Key, DocCount = g.Sum(dc => dc.DocCount)});

Answer 4

试试这个;

var anotherlist = list1.GroupBy(g => g.Name)
                  .Select(s => new
                  {
                      Name = s.Key,
                      DocCount = s.Sum(i => i.DocCount)
                  });

简单地说，通过基于DocCount的分组获得Name及其Name属性的总和。

Answer 5

var result= from item in list1
            group item by item.Name
            into g
            select g;
var groupedInfo = result.SelectMany(group => group);
foreach(var g in groupedInfo)
{
     //Do Summation
}

Answer 6

这是另一种做同样的方式

var sumOfDocs = from doc in list1 group doc by doc.Name into g 
                select new { DocName = g.Key, DocSum = g.Sum(i => i.DocCount) };

在linq中分组

6 个答案: