我有一个MySQL数据库,我需要搜索交易号码(它显示我的姓名,电子邮件和item_name)或搜索我的电子邮件地址和名称和购买日期,然后我会给我交易号码和item_name - 除非电子邮件,姓名和购买日期都正确,否则我不希望出现任何问题。
我的数据库中的字段是:
iname
iemail
itransaction_id
item_name
有人可以帮忙.... 这就是我现在拥有的......
<html>
<head>
<title>Search</title>
</head>
<body bgcolor=#ffffff>
<h2>Search</h2>
<form name="search" method="post" action="findme.php">
Seach for: <input type="text" name="find" />
<input type="submit" name="search" value="Search" />
</form>
</body>
</html>
另存为findme.html
下:
<html>
<head><title>Searching for a student...</title>
</head>
<body bgcolor=#ffffff>
<?php
echo "<h2>Search Results:</h2><p>";
//If they did not enter a search term we give them an error
if ($find == "")
{
echo "<p>You forgot to enter a search term!!!";
exit;
}
// Otherwise we connect to our Database
mysql_connect("xxxx.com", "xxxx", "xxxxpw") or die(mysql_error());
mysql_select_db("xxxx") or die(mysql_error());
// We perform a bit of filtering
$find = strtoupper($find);
$find = strip_tags($find);
$find = trim ($find);
//Now we search for our search term, in the field the user specified
$iname = mysql_query("SELECT * FROM ibn_table WHERE upper($field) LIKE'%$find%'");
//And we display the results
while($result = mysql_fetch_array( $iname ))
{
echo $result['firstname'];
echo " ";
echo $result['lastname'];
echo "<br>";
echo $result['idnumber'];
echo "<br>";
echo "<br>";
}
//This counts the number or results - and if there wasn't any it gives them a little message explaining that
$anymatches=mysql_num_rows($iname);
if ($anymatches == 0)
{
echo "Sorry, but we can not find an entry to match your query...<br><br>";
}
//And we remind them what they searched for
echo "<b>Searched For:</b> " .$find;
//}
?>
</body>
</html>
保存为findme.php
这是我目前得到的错误:
搜索结果:
警告:mysql_fetch_array():提供的参数不是第31行/hermes/bosweb25a/b409/ipg.bexgroupcouk/silverliningnetworks/Database/findme.php中的有效MySQL结果资源
警告:mysql_num_rows():提供的参数不是第43行/hermes/bosweb25a/b409/ipg.bexgroupcouk/silverliningnetworks/Database/findme.php中的有效MySQL结果资源 抱歉,我们找不到符合您查询的条目...
搜索:CARYS
答案 0 :(得分:2)
SELECT * FROM ibn_table WHERE itransaction_id LIKE '%$find%'
请注意LIKE和'%$ find%'
答案 1 :(得分:0)
我有三个你只是检查..
<html>
<head><title>Searching for a student...</title>
</head>
<body bgcolor=#ffffff>
<?php
include "config.php";
echo "<h2>Search Results:</h2><p>";
if(isset($_POST['search']))
{
$find =$_POST['find'];
//If they did not enter a search term we give them an error
if ($find == "")
{
echo "<p>You forgot to enter a search term!!!";
exit;
}
// Otherwise we connect to our Database
// We perform a bit of filtering
$find = strtoupper($find);
$find = strip_tags($find);
$find = trim ($find);
//Now we search for our search term, in the field the user specified
$iname = mysql_query("SELECT * FROM ibntable WHERE name LIKE'%$find%'")
or die(mysql_error());
//And we display the results
while($result = mysql_fetch_array( $iname ))
{
echo "id :" .$result['fname'];
echo "<br> ";
echo "name :".$result['lname'];
echo "<br>";
echo "name :".$result['middlename'];
echo "<br>";
echo "<br>";
}
//This counts the number or results - and if there wasn't any it gives them a little message explaining that
$anymatches = mysql_num_rows($iname);
if ($anymatches == 0)
{
echo "Sorry, but we can not find an entry to match your query...<br><br>";
}
//And we remind them what they searched for
echo "<b>Searched For:</b> " .$find;
//}
}
?>
</body>
</html>
答案 2 :(得分:0)
就像后续行动一样,我有同样的错误(php脚本显示为文本)和我修复它的方式是我检查了我用于我的网页的网址(这假设我正在运行我的WAMP来自我的本地电脑)。
您应该通过'localhost / somewebpage.html'格式而不是'file:/// C:/wamp/www/somewebpage.html'格式访问您的网页。如果从系统托盘中的WAMP服务器菜单转到www文件夹并双击您尝试运行的html页面,它将打开到'file:/// C:/wamp/www/somewebpage.html '格式。
很明显,解决这个问题的方法是打开浏览器并手动输入“localhost / somewebpage.html”来查看webapge。以这种方式运行它会强制它运行可以处理php的Apache服务器。以另一种方式运行它会强制页面完全从浏览器运行,并且您的Web浏览器不是Web服务器,因此它将php脚本作为纯文本处理并显示在您的页面上。