Silverlight HTTP POST

时间:2009-10-07 00:23:39

标签: silverlight

我只想在http://www.test.com/test.asp?test1=3上执行http发布。这是我一直在尝试使用的代码:

    private void pif_test_conn()
    {


        Uri url = new Uri("http://www.test.com/test.asp?test1=3", UriKind.Absolute);



        if (httpResult == true)
        {


            HttpWebRequest request = (HttpWebRequest)HttpWebRequest.Create(url);
            request.ContentType = "application/x-www-form-urlencoded";
            request.Method = "POST";
           request.BeginGetResponse(new AsyncCallback(ReadCallback), request); 

        }



        return ;
    }


   private void ReadCallback(IAsyncResult asynchronousResult)
    {


        HttpWebRequest request = (HttpWebRequest)asynchronousResult.AsyncState;


        HttpWebResponse response =  (HttpWebResponse)request.EndGetResponse(asynchronousResult);

        using (StreamReader streamReader1 =  new StreamReader(response.GetResponseStream()))
        {

            string resultString = streamReader1.ReadToEnd();

             MessageBox.Show("Using HttpWebRequest: " + resultString, "Found", MessageBoxButton.OK);             
        }

    }

当我执行此代码时,我的程序会触发Application_UnhandledException事件。不确定我做错了什么。

4 个答案:

答案 0 :(得分:6)

您是否想要发布给其他主持人?这种行为可能会导致XSS安全问题,因此无法使用。


string responseValue = "";
AutoResetEvent syncRequest = new AutoResetEvent(false);
Uri address = new Uri(HtmlPage.Document.DocumentUri, "/sample.aspx");

WebRequest request = WebRequest.Create(address);
request.Method = "POST";
request.BeginGetRequestStream(getRequestResult =>
{
    // Send packet data
    using (Stream post = request.EndGetRequestStream(getRequestResult))
    {
        post.Write(buffer, 0, buffer.Length);
        post.Close();
    }

    // wait for server response
    request.BeginGetResponse(getResponseResult =>
    {
        WebResponse response = request.EndGetResponse(getResponseResult);
        responseValue=new StreamReader(response.GetResponseStream()).ReadToEnd();

        syncRequest.Set();

    }, null);

}, null);

syncRequest.WaitOne();

MessageBox.Show(
    "Using WebRequest: " + responseValue, 
    "Found", MessageBoxButton.OK);

HTH

答案 1 :(得分:4)

您只能将HTTP请求发送到您的应用来自的域。

此限制可防止XSS攻击。

答案 2 :(得分:1)

关于Rubens' answer

如果您离开SyncRequest.WaitOne()来电,则通话死锁,至少在Silverlight 4.0中。

答案 3 :(得分:0)

要发送HTTP POST,您需要通过调用BeginGetRequestStream方法将POST数据写入请求。

这可能是你获得例外的原因;请告诉我们您正在寻找更具体的答案的例外情况。