Question

我正在使用clojure中的一个项目，它可以与任何java类互操作，所以我的问题的答案可能是java或clojure。

基本上我需要能够根据给定的分隔符（它将超过一个字符）将字符串拆分为组件，但同时保留分隔符。

例如：

splitting "test:test:test" on ":"  => [ "test" ":" "test" ":" "test" ]
splitting "::test::test::" on "::" => [ "::" "test" "::" "test" "::" ]

我使用clojure的clojure.string/split来使用壁橱，但它实际上并没有返回分隔符。第二个最接近的是使用StringTokenizer，它确实返回分隔符但不接受多字符分隔符。

有没有人知道任何解决方案，然后将字符串分解为一系列字符并对其进行奇怪的缩减？

Answer 1

这是一个构建正则表达式以匹配分隔符之前和之后的间隙的版本，而不是分隔符字符串本身（假设d中没有正则表达式特殊字符）：

=> (defn split-with-delim [s d]
     (clojure.string/split s (re-pattern (str "(?=" d ")|(?<=" d ")"))))
#'user/split-with-delim
=> (split-with-delim "test:test:test" ":")
["test" ":" "test" ":" "test"]
=> (split-with-delim "::test::test::" "::")
["" "::" "test" "::" "test" "::"]

Answer 2

(defn split-it [s d]
  (interpose d (str/split s (re-pattern d))))

(split-it "test:test:test" ":")
=> ("test" ":" "test" ":" "test")

(split-it "::test::test::" "::")
=> ("" "::" "test" "::" "test")

Java / clojure：多个字符分隔符，并保留分隔符

2 个答案: