好吧，我是Java编程的新手，并且遵循我在这里看到的一些技巧，我将这段代码用于测验游戏：
public class OtherActivity extends Activity {
TextView textView1, textView2;
Button btn1, btn2, btn3, btn4;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_other);
textView1 = (TextView) findViewById(R.id.textView1);
textView2 = (TextView) findViewById(R.id.textView2);
btn1 = (Button) findViewById(R.id.btn1);
btn2 = (Button) findViewById(R.id.btn2);
btn3 = (Button) findViewById(R.id.btn3);
btn4 = (Button) findViewById(R.id.btn4);
final ArrayList<Question> qsts = new ArrayList<Question>();
qsts.add(Question.q1);
qsts.add(Question.q2);
qsts.add(Question.q3);
qsts.add(Question.q4);
qsts.add(Question.q5);
qsts.add(Question.q6);
final Random rng = new Random();
final List<Integer> generated = new ArrayList<Integer>();
int nxt = rng.nextInt(6);
generated.add(nxt);
final Question nextQuestion = qsts.get(nxt);
textView1.setText(nextQuestion.questionText);
final ArrayList<String> allAnswers = new ArrayList<String>();
allAnswers.add(nextQuestion.correctAnswerText);
allAnswers.add(nextQuestion.wrongAnswer1);
allAnswers.add(nextQuestion.wrongAnswer2);
allAnswers.add(nextQuestion.wrongAnswer3);
Collections.shuffle(allAnswers);
btn1.setText(allAnswers.get(0));
btn2.setText(allAnswers.get(1));
btn3.setText(allAnswers.get(2));
btn4.setText(allAnswers.get(3));
btn1.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
if(allAnswers.get(0) == nextQuestion.correctAnswerText){
textView2.setText("CORRECT ANSWER, MAN!");
while(true){
int nxt = rng.nextInt(6);
if (!generated.contains(nxt)){
generated.add(nxt);
Question nextQuestion = qsts.get(nxt);
textView1.setText(nextQuestion.questionText);
ArrayList<String> allAnswers = new ArrayList<String>();
allAnswers.add(nextQuestion.correctAnswerText);
allAnswers.add(nextQuestion.wrongAnswer1);
allAnswers.add(nextQuestion.wrongAnswer2);
allAnswers.add(nextQuestion.wrongAnswer3);
Collections.shuffle(allAnswers);
btn1.setText(allAnswers.get(0));
btn2.setText(allAnswers.get(1));
btn3.setText(allAnswers.get(2));
btn4.setText(allAnswers.get(3));
break;
}
}
}
else{
textView2.setText("WRONG ANSWER, MAN!");
while(true){
int nxt = rng.nextInt(6);
if (!generated.contains(nxt)){
generated.add(nxt);
// ----> Integer nxt = rng.nextInt(6); <---- random nxt aqui!
Question nextQuestion = qsts.get(nxt);
textView1.setText(nextQuestion.questionText);
ArrayList<String> allAnswers = new ArrayList<String>();
allAnswers.add(nextQuestion.correctAnswerText);
allAnswers.add(nextQuestion.wrongAnswer1);
allAnswers.add(nextQuestion.wrongAnswer2);
allAnswers.add(nextQuestion.wrongAnswer3);
Collections.shuffle(allAnswers);
btn1.setText(allAnswers.get(0));
btn2.setText(allAnswers.get(1));
btn3.setText(allAnswers.get(2));
btn4.setText(allAnswers.get(3));
break;
}
}
}
}
});
//
// AND THE SAME METHOD TO THE BUTTONS btn2, btn3, btn4
//
// btn2 with a if (allAnswers1.get(1) == nextQuestion.correctAnswerText) { ...
// btn3 with a if (allAnswers1.get(2) == nextQuestion.correctAnswerText) { ...
// btn4 with a if (allAnswers1.get(3) == nextQuestion.correctAnswerText) { ...
//
}
}
我还有其他类代码：
public class Question {
String questionText;
String correctAnswerText;
String wrongAnswer1;
String wrongAnswer2;
String wrongAnswer3;
Question (String qst, String cAns, String wAns1, String wAns2, String wAns3){
questionText = qst;
correctAnswerText = cAns;
wrongAnswer1 = wAns1;
wrongAnswer2 = wAns2;
wrongAnswer3 = wAns3;
}
static Question q1 = new Question(
"Question 1",
"Correct answer - question 1",
"Wrong Answer 1 - question 1",
"Wrong Answer 2 - question 1",
"Wrong Answer 3 - question 1"
);
static Question q2 = new Question(
"Question 2",
"Correct answer - question 2",
"Wrong Answer 1 - question 2",
"Wrong Answer 2 - question 2",
"Wrong Answer 3 - question 2"
);
// ...
// and the same with q3, q4, q5 and q6
// ...
那么，你怎么看，我在确定正确答案方面遇到了问题。在第一个问题，它工作正常，但不是在此之后。我相信这个问题的发生是因为当我尝试比较allAnswers.get(0) == nextQuestion.correctAnswerText或者与ArrayList allAnswers的其他索引如（1），（2）或（3）时，为比较选择的“时段”仍然有第一个问题文字答案。那么，我该怎么办？
* Plus：代码变得非常大，我试图在onClickListener中放置if并与4个按钮的id进行比较，但它必须与其他函数一起使用，在外面onCreate，'因为ArrayList qsts （包含Question对象）没有被声明，我无法比较按钮点击的原因我必须声明一个不同的ArrayList。有更好的方法来做我想要的事情吗？
答案 0 :(得分：0)
对于拥有大代码的问题，我建议你单独使用onclicklistener并将button.setonclicklistener放在所有4个按钮中。
然后在点击监听器上，您将视图作为参数，该视图是一个按下的按钮。将其转换为按钮，然后获取按钮文本。那么你可以设置你在按钮动作中实现的其他领导者。
设置不同的方法来设置新问题，这样你只需要调用它，而不是多次编写相同的代码。
我希望它能解决你的两个问题。
答案 1 :(得分：0)
按照vikrant所说的说明进行操作。
此外，在用户选择任何选项时，请设置一个布尔变量，该值将更改。
通过检查布尔值，您可以获得用户是否已回答。
要检查相应的答案，您必须将所选值与正确的值进行比较。
享受编码。 ：）
答案 2 :(得分：0)
听到的是vikrant所说的例子
public class MyActivity extends Activity implements OnClickListener {
Question nextQuestion;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_other);
....... code
}
}
@Override
public void onClick(View v) {
Button b = (Button)v;
String buttonText = b.getText().toString();
if(buttonText.equals( nextQuestion.correctAnswerText ))
{
DoSomething();
return;
}else{
}
}
并且别忘了添加
Button button = (Button) findViewById(R.id.button_send);
button.setOnClickListener(this);
答案 3 :(得分：0)
如果您想创建测验应用程序，请检查此LINK。
另请查看此链接以了解existing database with an Android application
的使用情况如果您有任何问题，请告诉我。
祝你好运。