Question

我有一个搜索框，根据给定的输入在标题字段上执行搜索，因此用户建议所有可用的标题以插入的文本开头。它基于Lucene和Hibernate Search。它一直工作，直到输入空间。然后结果消失了。例如，我希望“学习H”给我“学习Hibernate”作为结果。但是，这不会发生。你能告诉我我应该在这里使用什么呢？

查询构建器：

QueryBuilder qBuilder = fullTextSession.getSearchFactory()
        .buildQueryBuilder().forEntity(LearningGoal.class).get();
  Query query = qBuilder.keyword().wildcard().onField("title")
        .matching(searchString + "*").createQuery();

  BooleanQuery bQuery = new BooleanQuery();
  bQuery.add(query, BooleanClause.Occur.MUST);
  for (LearningGoal exGoal : existingGoals) {
     Term omittedTerm = new Term("id", String.valueOf(exGoal.getId()));
     bQuery.add(new TermQuery(omittedTerm), BooleanClause.Occur.MUST_NOT);
  }
  @SuppressWarnings("unused")
  org.hibernate.Query hibQuery = fullTextSession.createFullTextQuery(
        query, LearningGoal.class);

Hibernate类：

@AnalyzerDef(name = "searchtokenanalyzer",tokenizer = @TokenizerDef(factory = StandardTokenizerFactory.class),
filters = {
  @TokenFilterDef(factory = StandardFilterFactory.class),
  @TokenFilterDef(factory = LowerCaseFilterFactory.class),
  @TokenFilterDef(factory = StopFilterFactory.class,params = { 
      @Parameter(name = "ignoreCase", value = "true") }) })
      @Analyzer(definition = "searchtokenanalyzer")
public class LearningGoal extends Node {

Answer 1

我找到了解决此问题的方法。这个想法是标记输入字符串并删除停用词。对于最后一个令牌，我使用关键字通配符创建了一个查询，对于之前的所有单词，我创建了一个TermQuery。这是完整的代码

    BooleanQuery bQuery = new BooleanQuery();
    Session session = persistence.currentManager();
    FullTextSession fullTextSession = Search.getFullTextSession(session);
    Analyzer analyzer = fullTextSession.getSearchFactory().getAnalyzer("searchtokenanalyzer");
    QueryParser parser = new QueryParser(Version.LUCENE_35, "title", analyzer);
    String[] tokenized=null;
    try {
    Query query=    parser.parse(searchString);
    String cleanedText=query.toString("title");
     tokenized = cleanedText.split("\\s");

    } catch (ParseException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    QueryBuilder qBuilder = fullTextSession.getSearchFactory()
            .buildQueryBuilder().forEntity(LearningGoal.class).get();
    for(int i=0;i<tokenized.length;i++){
         if(i==(tokenized.length-1)){
            Query query = qBuilder.keyword().wildcard().onField("title")
                    .matching(tokenized[i] + "*").createQuery();
                bQuery.add(query, BooleanClause.Occur.MUST);
        }else{
            Term exactTerm = new Term("title", tokenized[i]);
            bQuery.add(new TermQuery(exactTerm), BooleanClause.Occur.MUST);
        }
    }
        for (LearningGoal exGoal : existingGoals) {
        Term omittedTerm = new Term("id", String.valueOf(exGoal.getId()));
        bQuery.add(new TermQuery(omittedTerm), BooleanClause.Occur.MUST_NOT);
    }
    org.hibernate.Query hibQuery = fullTextSession.createFullTextQuery(
            bQuery, LearningGoal.class);

Answer 2

SQL使用与任何终端不同的通配符。在SQL '%'中替换零个或多个任何字符（在您使用'*'的终端中），而下划线'_'恰好替换一个字符（在您使用的终端中{{1}而不是）。 Hibernate不会翻译通配符。

因此，在第二行中，您必须将'?'替换为

matching(searchString + "*")

如何在Hibernate Search中搜索带通配符和空格的字段

2 个答案: