Question

print("this program will calculate the area")

input("[Press any key to start]")

width = int(input("enter width"))

while  width < 0 or width > 1000:
    print ("please chose a number between 0-1000")
    width = int(input("enter width"))

height = int(input("Enter Height"))

while  height < 0 or height > 1000:
    print("please chose a number between 0-1000")
    widht = int(input("Enter Height"))

area = width*height

print("The area is:",area

我添加了一条错误消息，用于输入低于或高于所述数字的数字，但是如果可能的话，我想向用户显示错误消息，如果他们输入一封信或什么都没有。

Answer 1

尝试在try中包装行输入行，但不包括：

try:
 width = int(input("enter width"))
except:
 width = int(input("enter width as integer"))

或更好：将其包装在函数中：

def size_input(message):
   try:
      ret = int(input(message))
      return ret
   except:
      return size_input("enter a number")

width = size_input("enter width")

Answer 2

您可以使用try-except，int()如果传递给它的参数无效，则会引发异常：

def valid_input(inp):
    try:
        ret=int(inp)
        if not 0<ret<1000:
            print ("Invalid range!! Try Again")
            return None
        return ret
    except:
        print ("Invalid input!! Try Again")
        return None
while True:
    rep=valid_input(input("please chose a number between 0-1000: "))
    if rep:break
print(rep)

<强>输出：

please chose a number between 0-1000: abc
Invalid input!! Try Again
please chose a number between 0-1000: 1200
Invalid range!! Try Again
please chose a number between 0-1000: 123abc
Invalid input!! Try Again
please chose a number between 0-1000: 500
500

Python-整数输入，输入字母的错误消息

2 个答案: