Question

我有多个连接，我有一个存储库类。我希望存储库类可以访问多个连接。它用于需要从多个数据库主机获取数据的报告。

config.yml

doctrine:
    dbal:
        default_connection:  default
        connections:
          default:
              driver:   "%db_default_driver%"
              host:     "%db_default_host%"
              etc..
          bookings:
              driver:   "%db_readonly_bookings_driver%"
              host:     "%db_readonly_bookings_host%"
              etc ...
          sessions:
              etc..

SalesJournalRepistory.php

namespace Portal\SalesJournalBundle\Repository;

use Doctrine\ORM\EntityRepository;

class SalesJournalRepository extends EntityRepository 
{

  public $connDefault   = null;
  public $connBookings  = null;
  public $connSessions  = null;


  function __construct()
  {
    // this is where I get the error
    $this->connDefault  = $this->getManager('default')->getConnection();
    $this->connBookings = $this->getManager('bookings')->getConnection();
    $this->connSessions = $this->getManager('sessions')->getConnection();
  }

  function testQuery(){
     $sql = "SELECT * FROM testTableBookings LIMIT 10";
     $stmt = $this->connBookings->prepare($sql);
     $results = $stmt->fetchAll();

     print_r($results);
  }

  function testQuery2(){
     $sql = "SELECT * FROM testTableSessions LIMIT 10";
     $stmt = $this->connSessions->prepare($sql);
     $results = $stmt->fetchAll();

     print_r($results);
  }


}

我可以通过控制器使其工作

$connDefault  = $this->getDoctrine()->getManager('default')->getConnection();
$connBookings = $this->getDoctrine()->getManager('bookings')->getConnection();

然而我希望能够从存储库运行它。我得到以下错误

PHP Fatal error:  Call to a member function getConnection() on a non-object

我认为这可能会给人一些线索？ enjecting entities但是我有点困惑，不确定是不是？

Answer 1

EntityRepository应该只关注其拥有的实体（和经理） - 所以将您的实体存储库与您的实体经理混合真的不是可行的方法。我建议你创建一个服务并注入Doctrine - 然后你可以查询你想要的任何东西。例如：

配置

[config.yml / services.yml]
services:
   sales_journal:
      class: Acme\DemoBundle\Service\SalesJournal
       arguments: ['@doctrine']

服务

[Acme\DemoBundle\Service\SalesJournal.php]

namespace Acme\DemoBundle\Service;

public class SalesJournal {

    private $connDefault;
    private $connBookings;
    private $connSessions;


    function __construct($doctrine)
    {
        $this->connDefault = $doctrine->getManager('default')->getConnection();
        $this->connBookings = $doctrine->getManager('bookings')->getConnection();
        $this->connSessions = $doctrine->getManager('sessions')->getConnection();
    }

    function testQuery()
    {
        $sql = "SELECT * FROM testTableBookings LIMIT 10";
        $stmt = $this->connBookings->prepare($sql);
        $results = $stmt->fetchAll();

        print_r($results);
    }

    function testQuery2()
    {
        $sql = "SELECT * FROM testTableSessions LIMIT 10";
        $stmt = $this->connSessions->prepare($sql);
        $results = $stmt->fetchAll();

        print_r($results);
    }
}

然后从您的控制器或您想要使用该服务的地方：

// get the service
$sales_journal = $this->get('sales_journal');
// call relevent function
$sales_journal->testQuery();

Answer 2

您应该将要在控制器中使用的实体管理器设置为getRepository方法的第二个参数，如下所示：

$repository = $this->getDoctrine()->getRepository('PortalSalesJournalBundle:SalesJournal', 'bookings');

并在存储库类中访问该实体管理器的连接，如下所示：

namespace Portal\SalesJournalBundle\Repository;

use Doctrine\ORM\EntityRepository;

class SalesJournalRepository extends EntityRepository 
{
    function testQuery(){
        $connection = $this->getEntityManager()->getConnection();
    }
}

symfony2 - 在存储库或类中使用多个连接

2 个答案: