如果声明代码问题

时间:2013-03-07 15:33:04

标签: java if-statement

我的教授给了我以下代码。

public static void main(String[] args) {

    Customer customer;
    Transaction transaction;
    double withdrawalAmount = 0;

    boolean finished = false;

    while (finished == false)
    {
        // Menu Display and Get user input
        int inputInt = 0;
        while (inputInt == 0)
        {
            inputInt = displayMenuAndGetInput();

                    // if the input is out of range
                    if ((inputInt < 1) || (inputInt > 8))
                    {
                            System.out.println("\nThe input is out of range!");
                            System.out.println();
                            inputInt = 0;
                    }
            } //end while

            // switch to correspondence function
            switch (inputInt)

            {
                case 1:
                    customer = createPersonalCustomer();
                    System.out.println("\nThe Personal customer has been created: \n" + newPC.toString());
                    customers.add(customer);
                    break;
                case 2:
                    customer = createCommercialCustomer();
                    System.out.println("\nThe Commercial customer has been created: \n" + newCC.toString());
                    customers.add(customer);
                    break;
                case 3:
                    transaction = recordTransaction();
                    if(transaction != null)
                        System.out.println("\nThe Transaction has been created: \n" + trans.toString());
                    else
                        System.out.println("\nThe ID could not be found.");
                    break;
                case 4:
                    withdrawalAmount = makeWithdrawal();
                    if(withdrawalAmount > 0)
                        System.out.println("\nAmount withdrawn from this account: " + moneyFormat.format(acct.getMakeWithdrawal()) + "\n");
                    else
                        System.out.println("\nThe ID could not be found.");
                    break;
                case 5:
                    displayCustomer();
                    break;
                case 6:
                    displayCustomerSummary();
                    break;
                case 7:
                    displayGrandSummary();
                    break;
                case 8:
                    // exit
                    finished = true;
                    break;
                default:
                    System.out.println("Invalid Input!");

                    break;
            } // end switch
    } // end while

}

我应该采取以下代码

// Create a new Transaction
public static Transaction recordTransaction(){}

并创建一个适用于以下场景的循环:

输入客户ID,如果客户ID在阵列中不匹配,则会生成案例3中读出的错误并显示主菜单。如果客户ID有效,则用户输入以下输入信息。

以下是我的代码

public static Transaction recordTransaction(){

System.out.println("Enter the customer ID to create the transaction > ");
    long customerID = scan.nextLong();

    for (Customer c : customers) {
        if (c.getCustomerID() == customerID) {
            if (trans != null) {

            System.out.println("\nEnter the weight of gold > ");
                Transaction.goldWt = scan.nextDouble();

                System.out.println("\nEnter the weight of platinum > ");
                Transaction.platinumWt = scan.nextDouble();

                System.out.println("\nEnter the weight of silver > ");
                Transaction.silverWt = scan.nextDouble();
                }
        }
            return null; 
}

Anywho,我已经通过多种方式运行,我的代码将接受无效且有效的客户ID,或者它不会接受无效或有效的客户ID。  我知道我可能会忽略一些事情,这就是我迫切要求论坛帮助的原因。在编程时我有OCD倾向,这是我的第一个介绍java类,所以我不熟悉这门语言。过去两天我一直坚持这个问题。请帮忙。

3 个答案:

答案 0 :(得分:1)

您需要在方法new Transaction()中实例化recordTransaction()并在适当的时候返回。

public static Transaction recordTransaction(){

    System.out.println("Enter the customer ID to create the transaction > "); long customerID = scan.nextLong();

    for (Customer c : customers) {
        if (c.getCustomerID() == customerID) {
            Transaction trans = new Transaction();

            System.out.println("\nEnter the weight of gold > ");
            trans.goldWt = scan.nextDouble();

            System.out.println("\nEnter the weight of platinum > ");
            trans.platinumWt = scan.nextDouble();

            System.out.println("\nEnter the weight of silver > ");
            trans.silverWt = scan.nextDouble();

            return trans;
        }
    }
    return null; 
}

答案 1 :(得分:0)

关于您的代码的一些评论:

if (trans != null) {

什么是“反式”?我想它必须引用一个Transaction实例。

Transaction.goldWt = ...

不应该是“trans.goldWt”吗? (当然,植物和银也是一样的)。如果它真的是Transaction.goldWt那么你总是改变那个单一的价值。

return null;

你永远不会返回任何东西,因此调用代码总是变为“无ID”。你不应该“return trans”吗?

答案 2 :(得分:0)

问题是由正在创建的每个帐户的随机customerID的getter和setter方法生成的。

谢谢 的Merci!