我需要一些帮助。我很反思。我们正在使用第三方api,它返回一个名为“AddressList”的类。它的公共属性字面上称为Address1,Address1Name,Address1Desc,Address2,Address2Name,Address2Desc,Address3,Address3Name,Address3Desc,... Address99,Address99Name,Address99Desc ..还有一些其他属性。我有一个名为“SimpleAddress”的类,它只有3个属性(地址,名称,描述)。我想要做的是当我返回“AddressList”类时,我想通过AddressDesc99循环AddressDesc1 ...并且无论哪个都不为null或空,我想创建一个“SimpleAddress”的实例,填充它的属性,并将其添加到列表...有人能指出我正确的方向吗?显然,如果“AddressList”是某种集合,那会更好,但遗憾的是它不是。它是从大型机的返回字符串生成的。
感谢您的帮助, 〜在圣地亚哥
答案 0 :(得分:6)
List<SimpleAddress> addresses = new List<SimpleAddress>();
string addressPropertyPattern = "Address{0}";
string namePropertyPattern = "Address{0}Name";
string descPropertyPattern = "Address{0}Desc";
for(int i = 1; i <= MAX_ADDRESS_NUMBER; i++)
{
System.Reflection.PropertyInfo addressProperty = typeof(AddressList).GetProperty(string.Format(addressPropertyPattern, i));
System.Reflection.PropertyInfo nameProperty = typeof(AddressList).GetProperty(string.Format(namePropertyPattern, i));
System.Reflection.PropertyInfo descProperty = typeof(AddressList).GetProperty(string.Format(descPropertyPattern, i));
SimpleAddress address = new SimpleAddress();
address.Address = (string)addressProperty.GetValue(yourAddressListObject, null);
address.Name = (string)nameProperty.GetValue(yourAddressListObject, null);
address.Description = (string)descProperty.GetValue(yourAddressListObject, null);
addresses.Add(address);
}
答案 1 :(得分:3)
首先获取相关类的类型并调用GetProperties方法。
PropertyInfo[] properties = myMainframeObject.GetType().GetProperties();
每个PropertyInfo都有一个可用于匹配的Name属性(字符串)。遍历所有属性,并编写创建SimpleAddress新实例的代码。
在此循环中,您可以访问大型机对象并提取所需的属性值:
// imagine that in this case, 'p' is a PropertyInfo that represents Address2Name
var simpleAddress = new SimpleAddress();
simpleAddress.Name = p.GetValue(myMainframeObject, null);
(null永远不会用于普通属性 - 它适用于索引属性。)
答案 2 :(得分:2)
您应该可以执行以下操作:
List<SimpleAddress> CreateList(AddressList address)
{
List<SimpleAddress> values = new List<SimpleAddress>();
Type type = address.GetType();
for (int i=1;i<=99;++i)
{
string address = type.GetProperty("Address" + i.ToString()).GetValue(address,null).ToString();
string addressDesc = type.GetProperty("Address" + i.ToString() + "Desc").GetValue(address,null).ToString();
string addressName = type.GetProperty("Address" + i.ToString() + "Name").GetValue(address,null).ToString();
if (!string.IsNullOrEmpty(addressDesc) || !string.IsNullOrEmpty(addressName) || !string.IsNullOrEmpty(address) )
value.Add(new SimpleAddress(address,addressDesc,addressName));
}
return values;
}
答案 3 :(得分:1)
未经测试(出于显而易见的原因),但类似于:
List<SimpleAddress> newList = new List<SimpleAddress>();
AddressList list = ...
Type type = list.GetType();
PropertyInfo prop1, prop2, prop3;
int index = 1;
while((prop1 = type.GetProperty("Address" + index)) != null
&& (prop2 = type.GetProperty("Address" + index + "Name")) != null
&& (prop3 = type.GetProperty("Address" + index + "Desc")) != null) {
string addr = (string) prop1.GetValue(list, null),
name = (string) prop2.GetValue(list, null),
desc = (string) prop3.GetValue(list, null);
if(addr == null || name == null || desc == null) {
continue; // skip but continue
}
SimpleAddress newAddr = new SimpleAddress(addr, name, desc);
newList.Add(newAddr);
index++;
}
答案 4 :(得分:1)
如果你想使用linq
public static class MyTools
{
public static TReturn GetValue<TReturn>(this object input,
string propertyName)
{
if (input == null)
return default(TReturn);
var pi = input.GetType().GetProperty(propertyName);
if (pi == null)
return default(TReturn);
var val = pi.GetValue(input, null);
return (TReturn)(val == null ? default(TReturn) : val);
}
public static string GetString(this object input, string propertyName)
{
return input.GetValue<string>(propertyName);
}
public static List<SimpleAddress> GetAddress(this MyObject input)
{
return (
from i in Enumerable.Range(1, 2)
let address = input.GetString("Address" + i.ToString())
let name = input.GetString("Address" + i.ToString() + "Name")
let desc = input.GetString("Address" + i.ToString() + "Desc")
select new SimpleAddress() { Address = address,
Name = name,
Description = desc }
).ToList();
}
}
答案 5 :(得分:0)
var addrList = new AddressList
{
Address1Name = "ABC",
Address1Desc = "DEF",
Address1 = "GHI",
Address3Name = "X",
Address3Desc = "Y",
Address3 = "Z"
};
var addresses =
from i in Enumerable.Range(1, 99)
let desc = typeof(AddressList).GetProperty(string.Format("Address{0}Desc", i)).GetValue(addrList, null) as string
let name = typeof(AddressList).GetProperty(string.Format("Address{0}Name", i)).GetValue(addrList, null) as string
let address = typeof(AddressList).GetProperty(string.Format("Address{0}", i)).GetValue(addrList, null) as string
where !string.IsNullOrEmpty(address)
select new SimpleAddress
{
Name = name,
Description = desc,
Address = address
};