当我尝试使用我的restTemplate.postForEntity时,我收到了404错误请求 我的错是什么?
代码:
Servercaller:
public ServerError login(String username, String password) {
User user = new User();
user.setUsername(username);
user.setPassword(password);
try {
String URL = "http://"+ipAddress+"/ProjectTeamF-1.0/service/login.json";
Object[] params = new Object[]{URL,user};
new login().execute(params);
} catch (ResourceAccessException rae) {
receivedUser = null;
return ServerError.ServerNotFound;
} catch (HttpServerErrorException hsee) {
receivedUser = null;
return ServerError.WrongData;
} catch(RestClientException rce){
receivedUser = null;
return ServerError.WrongData;
} catch (Exception e) {
System.out.println("error " + e);
receivedUser = null;
return ServerError.OtherError;
}
return ServerError.NoError;
}
的AsyncTask:
public class login extends AsyncTask<Object[], Void, Void> {
public ServerCaller sc = ServerCaller.getInstance();
public User body;
@Override
protected Void doInBackground(Object[]... params) {
String message = "";
try {
HttpHeaders requestHeaders = new HttpHeaders();
requestHeaders.setContentType(MediaType.APPLICATION_JSON);
HttpEntity<User> _entity = new HttpEntity<User>((User)params[0][1], requestHeaders);
RestTemplate templ = new RestTemplate();
templ.setRequestFactory(new HttpComponentsClientHttpRequestFactory());
templ.getMessageConverters().add(new MappingJacksonHttpMessageConverter());
ResponseEntity<User> _response = templ.postForEntity(params[0][0].toString(), _entity, User.class); //null here in order there wasn't http converter errors because response type String and [text/html] for JSON are not compatible;
body = _response.getBody();
return null;
} catch (Exception e) {
message = e.getMessage();
return null;
}
}
@Override
protected void onPostExecute(Void aVoid) {
super.onPostExecute(aVoid);
sc.setReceivedUser(body);
}
}
当我在templ.postForEntity()调试程序崩溃时。错误告诉我这是一个400 - 不好的请求。
谢谢!