First_mutableArray
是1,2,3,4,5,6
Second_MutableArray
为2,4,6,8,0,12
如何获得这样的输出
First_mutableArray
是1,2,3,4,5,6,8,0,12
?
答案 0 :(得分:9)
订购版本:
NSMutableOrderedSet *first = [NSMutableOrderedSet orderedSetWithObjects:@"1",@"2",@"3",@"4",@"5",@"6",nil];
NSOrderedSet *second = [NSOrderedSet orderedSetWithObjects:@"2",@"4",@"6",@"8",@"0",@"12",nil];
[first unionOrderedSet:second];
变量第一个将包含结果。
答案 1 :(得分:2)
尝试:
NSMutableArray *first=[NSMutableArray arrayWithArray:@[@"1",@"2",@"3",@"4",@"5",@"6"]];
NSMutableArray *second=[NSMutableArray arrayWithArray:@[@"2",@"4",@"6",@"8",@"0",@"12"]];
for (id obj in second) {
if (![first containsObject:obj]) {
[first addObject:obj];
}
}
NSLog(@"%@",first);
编辑:
NSMutableArray *first=[NSMutableArray arrayWithArray:@[@"1",@"2",@"3",@"4",@"5",@"6"]];
NSMutableArray *second=[NSMutableArray arrayWithArray:@[@"2",@"4",@"6",@"8",@"0",@"12"]];
NSMutableOrderedSet *firstSet=[NSMutableOrderedSet orderedSetWithArray:first];
NSOrderedSet *secondSet=[NSOrderedSet orderedSetWithArray:second];
[firstSet unionOrderedSet:secondSet];
first=[[firstSet array] mutableCopy];
NSLog(@"%@",first);
* 归功于Mark Kryzhanouski
答案 2 :(得分:0)
将这两个数组合并使用下面的代码在combinedArray上删除重复项。
NSMutableArray* combinedArray = [NSMutableArray arrayWithArray:firstArray];
[combinedArray addObjectsFromArray: secondArray];
NSMutableArray *myUniqueArray = [NSMutableArray array];
for (id obj in combinedArray) {
if (![myUniqueArray containsObject:obj]) {
[myUniqueArray addObject:obj];
}
}
答案 3 :(得分:0)
使用此代码
NSMutableArray *array = [[NSMutableArray alloc]initWithObjects:@"1",@"2",@"3",@"4",@"5",@"6", nil];
NSMutableArray *array1 = [[NSMutableArray alloc]initWithObjects:@"2",@"4",@"6",@"8",@"0",@"12", nil];
for(int i = 0;i<array1.count;i++)
{
NSString *str = [array1 objectAtIndex:i];
if (![array containsObject:str])
{
[array addObject: str];
}else
{
NSLog(@"contins");
}
}
NSLog(@"%@",array);
答案 4 :(得分:0)
您可以使用 NSMutableSet 来执行此操作:
NSMutableSet *firstSet = [NSMutableSet setWithArray:First_mutableArray];
NSMutableSet *secondSet = [NSMutableSet setWithArray:Second_MutableArray];
[firstSet unionSet:secondSet];
NSArray *uniqueArray = [firstSet allObjects];
答案 5 :(得分:0)
你好。使用NSSet将比迭代每个数组并添加不匹配的对象提供更好的性能。
NSArray *arr1 = @[@1,@2,@3,@4,@5,@6];
NSArray *arr2 = @[@2,@4,@6,@8,@0,@12];
NSMutableSet *set = [[NSMutableSet alloc] initWithArray:arr1];
[set addObjectsFromArray:arr2];
// Unsorted
NSLog(@"set = %@", [set description]);
// Sorted
NSSortDescriptor *sort = [NSSortDescriptor sortDescriptorWithKey:@"self" ascending:YES];
NSArray *sortedArray = [set sortedArrayUsingDescriptors:[NSArray arrayWithObject:sort]];
NSLog(@"sortedArray = %@", [sortedArray description]);
答案 6 :(得分:0)
尝试以下方法:
NSMutableArray *first=[NSMutableArray arrayWithArray:@[@"1",@"2",@"3",@"4",@"5",@"6"]];
NSMutableArray *second=[NSMutableArray arrayWithArray:@[@"2",@"4",@"6",@"8",@"0",@"12"]];
NSMutableSet *firstSet = [NSMutableSet setWithArray:first];
NSMutableSet *secondSet = [NSMutableSet setWithArray:second];
[firstSet unionSet:secondSet];
NSArray *uniqueArray = [firstSet allObjects];