我有两个表父母和孩子之间有@oneTomany关系。 以下是我的表结构。
表格结构
CREATE TABLE `parent` (
`id_parent` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(255) DEFAULT NULL,
PRIMARY KEY (`id_parent`)
)
CREATE TABLE `child` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(255) DEFAULT NULL,
`parent_id` int(3) NOT NULL,
PRIMARY KEY (`id`),
KEY `fk_parent_child` (`group_id`),
CONSTRAINT `fk_parent_child` FOREIGN KEY (`parent_id`) REFERENCES `parent` (`id_parent`)
)
我为此创建了实体类,如下所示
家长班。
@Entity
@Table(name = "parent")
public class Parent {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id_parent")
private int id;
@Column(name = "name")
private String name;
@OneToMany(mappedBy = "defaultchild", fetch = FetchType.EAGER)
@Cascade({ CascadeType.SAVE_UPDATE, CascadeType.MERGE })
private Set<Child> childs;
//setter and getters.
}
儿童班。
@Entity
@Table (name = "child")
public class Report {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column (name = "id")
private int id;
@Column (name = "name")
private String name;
@ManyToOne
@Cascade({org.hibernate.annotations.CascadeType.SAVE_UPDATE,org.hibernate.annotations.CascadeType.MERGE})
@JoinColumn(name="parent_id")
private Parent defaultchild;
@ManyToMany(fetch = FetchType.LAZY)
@JoinTable(name = "group",joinColumns={@JoinColumn(name="fk_child_id")},inverseJoinColumns={@JoinColumn(name="fk_group_id")})
private Set<XXX> groups = new HashSet<XXX>(0);
//Setter and Getter methods
}
服务类
public UIGroup getParentByName(String name) {
return DAO.getParentByName(name);
}
@Transactional(readOnly = false, propagation = Propagation.REQUIRED)
public boolean updateParent(Parent parent) {
return DAO.updateParent(parent);
}
@Transactional(readOnly = false, propagation = Propagation.REQUIRED)
public boolean deleteParent(Parent parent) {
return DAO.deleteParent(parent);
}
DAO Class。
public UIGroup getParentByName(String name) {
Query query;
Parent parent = null;
try {
String queryString = " from Parent where name = :name";
query = sessionFactory.getCurrentSession().createQuery(queryString);
query.setParameter("name", name);
uiGroup = (Parent) query.uniqueResult();
} catch (Exception e) {
logger.error(e);
}
return parent;
}
public boolean updateParent(Parent parent) {
boolean result = true;
Session session = null;
Transaction tx = null;
try {
session = sessionFactory.getCurrentSession();
tx = session.beginTransaction();
session.merge(parent);
tx.commit();
session.flush();
} catch (HibernateException e) {
result = false;
logger.error(e);
}// end of try-catch block.
return result;
}
public boolean deleteParent(Parent parent) {
boolean result = true;
Session session = null;
try {
session = sessionFactory.getCurrentSession();
session.delete(parent);
} catch (HibernateException e) {
result = false;
logger.error( + e);
}
return result;
}
但是当我尝试调用以下代码时
Parent otherParent = Service.getParentByName("Other");
Parent parent = Service.getParentByName("XYZ");
//here I am assigning childs assign to XYX parent to other Parent
Set<Child> childs = new TreeSet<Child>(Child.COMPARE_BY_ID);
childs.addAll(otherParent.getchildes());
childs.addAll(parent.getchilde());
otherParent.setChilds(childs);
Service.updateParent(otherParent);
Service.deleteParent(parent);
我收到了以下错误。
错误 的
java.sql.BatchUpdateException: Cannot delete or update a parent row: a foreign key constraint fails (`database`.`child`, CONSTRAINT `fk_parent_child` FOREIGN KEY (`parent_id`) REFERENCES `child` (`id_parent`))
这意味着我的更新代码无法正常运行以下是Service.updateParent(otherParent)语句的日志
SELECT parent0_.id_parent AS id1_135_1_, parent0_.name AS name135_1_, childs1_.parent_id AS parent4_3_, childs1_.id AS id3_, childs1_.id AS id143_0_, childs1_.child_name AS child2_143_0_, childs1_.is_sea_child AS is3_143_0_, childs1_.parent_id AS parent4_143_0_
FROM ui_parent parent0_
LEFT OUTER JOIN child childs1_ ON parent0_.id_ui_parent=childs1_.parent_id
WHERE parent0_.id_parent=1
请帮帮我,我不知道这段代码出了什么问题 提前谢谢。
答案 0 :(得分:2)
我可能会写一个DAO方法moveAllChildren(String srcName,String dstName),如下所示:
public class ParentDAO {
@PersistenceContext
private EntityManager em;
public Parent findParentByName(name) {
TypedQuery<Parent> q = em.createQuery("select p from Parent where p.name = :name", Parent.class);
return q.setParameter("name", name).getSingleResult();
}
public void moveAllChildren(String srcName, String dstName) {
Parent src = findParentByName(srcName);
Parent dst = findParentByName(dstName);
Set<Child> children = new HashSet<Child>();
for (Child c: src.getChildren()) {
children.add(c);
}
src.getChildren().removeAll(children);
dst.getChildren().addAll(children);
}
}
一般情况下,使用Cascading时,明确添加和删除子项是一种良好做法,而不是说dst.setChildren(allChildren),以便让JPA有机会管理Relation的两端。如果你不这样做,你可能会认为孩子仍然认为src是他们的父母,然后你可能会看到你的数据库违反约束。
此外,尝试让JPA尽可能多地管理您的实体内容是一个好主意。所以我宁愿没有应用程序调用服务调用DAO来检索父项只移动他们的子项然后调用相同的服务调用相同的DAO将这些更改合并到数据库中。你最好将它作为DAO级别的低级操作实现,然后添加一个调用它来处理@Transaction的服务。
答案 1 :(得分:1)
如果您没有选择限制@Cascade
类型的具体原因,则可以选择切换为全部。
@Cascade({ CascadeType.ALL})
甚至只是
@OneToMany(cascade=CascadeType.ALL, mappedBy="defaultchild")
编辑:你有几次错误拼写'父母',修复它也不会有什么坏处。
答案 2 :(得分:0)
您尝试删除parent
但可能仍有childs
。在删除之前尝试清空childs
集合:
for(Child child : parent.getChilds()){
child.setParent(null);
}
parent.getChilds().clear();
Service.deleteParent(parent);
如果parent
仍有参考,则无法删除Child
。
答案 3 :(得分:0)
最终我在wallenborn的帮助下得到了解决方案并且链接
JPA not saving foreign key to @OneToMany relation
以下是我在课堂上所做的更改。
实体类。
@Entity
@Table(name = "parent")
public class Parent {
.....
@OneToMany(cascade = CascadeType.PERSIST,mappedBy = "defaultchild", fetch = FetchType.EAGER)
private Set<Child> childs;
//setter and getters.
}
@Entity
@Table (name = "child")
public class Child {
....
@ManyToOne
@JoinColumn(name="parent_id")
private Child defaultchild;
//Setter and Getter methods
}
我已经更改了wallenborn建议的服务和DAO课程,如下所示
服务类。
@Transactional(readOnly = false, propagation = Propagation.REQUIRED)
public void moveAllChildren(String srcName, String dstName) {
DAO.moveAllChildren(srcName, dstName);
}
DAO课程
public Parent findParentByName(name) {
TypedQuery<Parent> q = em.createQuery("select p from Parent where p.name = :name", Parent.class);
return q.setParameter("name", name).getSingleResult();
}
public void moveAllChildren(String srcName, String dstName) {
Parent src = findParentByName(srcName);
Parent dst = findParentByName(dstName);
Set<Child> children = new HashSet<Child>();
for (Child c: src.getChildren()) {
children.add(c);
}
src.getChildren().removeAll(children);
dst.getChildren().addAll(children);
}