我正在尝试使用此代码发送请求
protected void Authenticate(String mUsername, String mPassword)
{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://192.168.2.5:8000/mobile/");
try {
// Add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("username", mUsername));
nameValuePairs.add(new BasicNameValuePair("password", mPassword));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
System.out.println("this is the response "+response);
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
System.out.println("CPE"+e);
} catch (IOException e) {
// TODO Auto-generated catch block
System.out.println("IOE"+e);
}
}
我得到的是HttpResponse
,我正在努力实现正确的方式吗?如果是,我如何将该响应转换为jSON?
LOG-CAT
this is the response org.apache.http.message.BasicHttpResponse@2fb67110
答案 0 :(得分:4)
String jsonString = EntityUtils.toString(response.getEntity());
这就是你需要的
答案 1 :(得分:2)
这将对您有所帮助:
public class JSONParser {
static InputStream is = null;
static JSONObject jObj = null;
static String json = "";
// constructor
public JSONParser() {
}
// function get json from url
// by making HTTP POST or GET method
public JSONObject makeHttpRequest(String url, String method,
List<NameValuePair> params) throws Exception {
// Making HTTP request
try {
// check for request method
if (method == "POST") {
// request method is POST
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
httpPost.setEntity(new UrlEncodedFormEntity(params));
// new
HttpParams httpParameters = httpPost.getParams();
// Set the timeout in milliseconds until a connection is
// established.
int timeoutConnection = 10000;
HttpConnectionParams.setConnectionTimeout(httpParameters,
timeoutConnection);
// Set the default socket timeout (SO_TIMEOUT)
// in milliseconds which is the timeout for waiting for data.
int timeoutSocket = 10000;
HttpConnectionParams
.setSoTimeout(httpParameters, timeoutSocket);
// new
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
} else if (method == "GET") {
// request method is GET
DefaultHttpClient httpClient = new DefaultHttpClient();
String paramString = URLEncodedUtils.format(params, "utf-8");
url += "?" + paramString;
HttpGet httpGet = new HttpGet(url);
// new
HttpParams httpParameters = httpGet.getParams();
// Set the timeout in milliseconds until a connection is
// established.
int timeoutConnection = 10000;
HttpConnectionParams.setConnectionTimeout(httpParameters,
timeoutConnection);
// Set the default socket timeout (SO_TIMEOUT)
// in milliseconds which is the timeout for waiting for data.
int timeoutSocket = 10000;
HttpConnectionParams
.setSoTimeout(httpParameters, timeoutSocket);
// new
HttpResponse httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
}
} catch (UnsupportedEncodingException e) {
throw new Exception("Unsupported encoding error.");
} catch (ClientProtocolException e) {
throw new Exception("Client protocol error.");
} catch (SocketTimeoutException e) {
throw new Exception("Sorry, socket timeout.");
} catch (ConnectTimeoutException e) {
throw new Exception("Sorry, connection timeout.");
} catch (IOException e) {
throw new Exception("I/O error(May be server down).");
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
} catch (Exception e) {
throw new Exception(e.getMessage());
}
// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
throw new Exception(e.getMessage());
}
// return JSON String
return jObj;
}
}
你可以像这样使用上面的类: 例如:
public class GetName extends AsyncTask<String, String, String> {
String imei = "abc";
JSONParser jsonParser = new JSONParser();
@Override
protected void onPreExecute() {
super.onPreExecute();
}
protected String doInBackground(String... args) {
String name = null;
String URL = "http://192.168.2.5:8000/mobile/";
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("username", mUsername));
params.add(new BasicNameValuePair("password", mPassword));
JSONObject json;
try {
json = jsonParser.makeHttpRequest(URL, "POST", params);
try {
int success = json.getInt(Settings.SUCCESS);
if (success == 1) {
name = json.getString("name");
} else {
name = null;
}
} catch (JSONException e) {
name = null;
}
} catch (Exception e1) {
}
return name;
}
protected void onPostExecute(String name) {
Toast.makeText(mcontext, name, Toast.LENGTH_SHORT).show();
}
}
使用方法:
只需通过复制类代码来创建新的JSONParse类。
然后,您可以在应用程序的任何位置调用它,如第二个代码所示。
答案 2 :(得分:0)
这里你需要做什么
HttpResponse mHttpResponse = mHttpClient.execute(httppost);
StatusLine status = mHttpResponse.getStatusLine();
int response = status.getStatusCode();
答案 3 :(得分:0)
以下是blog的示例。希望这有帮助
if (response.getStatusLine().getStatusCode() != 200) {
throw new RuntimeException("Failed : HTTP error code : "
+ response.getStatusLine().getStatusCode());
}
BufferedReader br = new BufferedReader(
new InputStreamReader((response.getEntity().getContent())));
String output;
System.out.println("Output from Server .... \n");
while ((output = br.readLine()) != null) {
System.out.println(output);
}
httpClient.getConnectionManager().shutdown();