Question

我有一个存储纬度和经度的地方数据库。我想查询数据库以查找特定纬度（$requestedDistance）和经度（$latitude）的半径（$longitude）内的所有位置。

下面的查询有效，只返回此半径范围内的那些地方，但是我如何按距离排序，所以最接近的是？在过去，使用原始SQL我已经在SELECT语句中完成了计算并将其设置为'distance'然后使用HAVING distance < $requestedDistance ORDER BY distance，但是我不知道如何使用Doctrine Repository将计算添加到SELECT查询。

$d = $this->getDoctrine()->getRepository('XXXWebsiteBundle:Locations')->createQueryBuilder('l');
        $d
            ->add('where','l.enabled = 1')
            ->andWhere('( 3959 * acos( cos( radians('.$latitude.') )
                * cos( radians( l.latitude ) )
                * cos( radians( l.longitude )
                - radians('.$longitude.') )
                + sin( radians('.$latitude.') )
                * sin( radians( l.latitude ) ) ) ) < '.$requestedDistance);

       $result= $d->getQuery();

更新

感谢@Lazy Ants尝试了以下查询：

$d = $this->getDoctrine()->getRepository('XXXWebsiteBundle:Locations')->createQueryBuilder('l');
    $d
        ->select('l')
        ->addSelect(
            '( 3959 * acos(cos(radians(' . $latitude . '))' .
                '* cos( radians( l.latitude ) )' .
                '* cos( radians( l.longitude )' .
                '- radians(' . $longitude . ') )' .
                '+ sin( radians(' . $latitude . ') )' .
                '* sin( radians( l.latitude ) ) ) ) as distance'
        )
        ->andWhere('l.enabled = :enabled')
        ->setParameter('enabled', 1)
        ->andWhere('distance < :distance')
        ->setParameter('distance', $requestedDistance)
        ->orderBy('distance', 'ASC');

但是，它会返回以下错误：

`An exception occurred while executing 'SELECT COUNT(*) AS dctrn_count FROM 
(SELECT DISTINCT il0 FROM (SELECT l0_.id AS il0, l0_.name AS name2, l0_.address1 
AS address14, l0_.address2 AS address25, l0_.postcode AS postcode6, l0_.town AS 
town7, l0_.county AS county8, l0_.enabled AS enabled11, l0_.date_created AS 
date_created12, l0_.date_modified AS date_modified13, l0_.latitude AS 
latitude19, l0_.longitude AS longitude20, 3959 * ACOS(COS(RADIANS(53.51331889999999)) 
* COS(RADIANS(l0_.latitude)) * COS(RADIANS(l0_.longitude) - 
RADIANS(-2.935331099999985)) + SIN(RADIANS(53.51331889999999)) * 
SIN(RADIANS(l0_.latitude))) AS sclr21 FROM locations l0_ WHERE l0_.enabled = ? 
AND sclr21 < ? ORDER BY sclr21 ASC) dctrn_result) dctrn_table' with params 
{"1":1,"2":30}:

SQLSTATE[42S22]: Column not found: 1054 Unknown column 'sclr21' in 'where clause'`

Answer 1

    $d = $this->getDoctrine()->getRepository('XXXWebsiteBundle:Locations')->createQueryBuilder('l');
    $d
        ->select('l')
        ->addSelect(
            '( 3959 * acos(cos(radians(' . $latitude . '))' .
                '* cos( radians( l.latitude ) )' .
                '* cos( radians( l.longitude )' .
                '- radians(' . $longitude . ') )' .
                '+ sin( radians(' . $latitude . ') )' .
                '* sin( radians( l.latitude ) ) ) ) as distance'
        )
        ->andWhere('l.enabled = :enabled')
        ->setParameter('enabled', 1)
        ->having('distance < :distance')
        ->setParameter('distance', $requestedDistance)
        ->orderBy('distance', 'ASC');

Answer 2

你正在使用andWhere（）而没有where（）。

将andWhere（）替换为where（）。

如果某个属性映射到名为“sclr21”的列上，请同时检查您的实体定义，这样您就可以发现您遇到问题的属性。

Symfony2，Doctrine搜索和按距离排序

2 个答案: