我试图使用real_parser和以下ureal_policies解析实数:
template <typename T>
struct number_real_policies : qi::ureal_policies<T>
{
static bool const expect_dot = true;
template <typename Iterator, typename Attribute>
static bool
parse_nan(Iterator& first, Iterator const& last, Attribute& attr) {
return false;
}
template <typename Iterator, typename Attribute>
static bool
parse_inf(Iterator& first, Iterator const& last, Attribute& attr) {
return false;
}
};
它似乎完美地解析了我需要的实数格式的所有变体,但我注意到以下字符串也被接受:“。12345.e12”。
在小数部分接受两个点是否正常(它只适用于E / e之前的第二个点,并且E / e必须存在)?
提前致谢
答案 0 :(得分:1)
正如@llonesmiz在我的测试应用程序中正确指出的那样,它完全按照设计工作:
<强> Live On Coliru 强>
您好像忘记检查解析器退出代码?
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/karma.hpp>
namespace qi = boost::spirit::qi;
namespace karma = boost::spirit::karma;
typedef std::vector<double> attr_t;
template <typename T>
struct number_real_policies : qi::ureal_policies<T>
{
static bool const expect_dot = true;
template <typename Iterator, typename Attribute>
static bool
parse_nan(Iterator& first, Iterator const& last, Attribute& attr) {
return false;
}
template <typename Iterator, typename Attribute>
static bool
parse_inf(Iterator& first, Iterator const& last, Attribute& attr) {
return false;
}
};
template <typename It, typename Skipper = qi::space_type>
struct parser : qi::grammar<It, attr_t(), Skipper>
{
parser() : parser::base_type(start)
{
using namespace qi;
start %= *mydouble_;
BOOST_SPIRIT_DEBUG_NODE(start);
}
private:
qi::rule<It, attr_t(), Skipper> start;
qi::real_parser<double, number_real_policies<double> > mydouble_;
};
bool doParse(const std::string& input)
{
typedef std::string::const_iterator It;
auto f(begin(input)), l(end(input));
parser<It, qi::space_type> p;
attr_t data;
try
{
bool ok = qi::phrase_parse(f,l,p,qi::space,data);
if (ok)
{
std::cout << "parse success\n";
std::cout << "data: " <<
karma::format_delimited(karma::columns(3) [*karma::auto_], ' ', data) << "\n";
}
else std::cerr << "parse failed: '" << std::string(f,l) << "'\n";
if (f!=l) std::cerr << "trailing unparsed: '" << std::string(f,l) << "'\n";
return ok;
} catch(const qi::expectation_failure<It>& e)
{
std::string frag(e.first, e.last);
std::cerr << e.what() << "'" << frag << "'\n";
}
return false;
}
int main()
{
bool ok = doParse(
"0. 2. .3 \n "
"0.e7 2.e7 .3e7 \n"
"0.e-7 2.e-7 .3e-7 \n"
// shouldn't accept:
//"0..e7\n"
"0.3.e7\n"
);
return ok? 0 : 255;
}
输出:
parse success
data: 0.0 2.0 0.3
0.0 2.0e07 3.0e06
0.0 2.0e-07 3.0e-08
0.3
trailing unparsed: '.e7
'