Set objReadFile = objFSO.OpenTextFile(objFile.Path, ForReading)
strAll = Split(objReadFile.ReadAll, vbCrLf, -1, vbTextCompare) 'Gets each line from file
i = LBound(strAll)
Do While i < UBound(strAll)
If (InStr(1, strAll(i), "DAU SNo.-C0", vbTextCompare) > 0) Then
i = i + 4 'Skip 4 lines to get to first SN
Do Until InStr(1, strAll(i), "+", vbTextCompare) > 0 'Loop until line includes "+"
strSNO = Split(strAll(i), "|", -1, vbTextCompare)
'put strSNO into next cell in column A
**objSheet.Cells.Offset(1,0).Value = Trim(strSNO(1))**
i = i + 1
Loop
End If
i = i + 1
Loop
此代码成功拆分文本文件,并将我想要的两个值放在strSNO(1)和strSNO(2)中。我想将它们写入A列第2行和第B行第2行,然后在循环的下一次迭代中将第3行中的下一个值放入。我尝试了偏移方法,它给出了错误。我找到的所有帮助都是针对VBA的。任何人都可以告诉我什么放在代码是粗体的地方修复它?
编辑:
解决了它。这就是我所做的:
strAll = Split(objReadFile.ReadAll, vbCrLf, -1, vbTextCompare) 'Gets each line from file
i = LBound(strAll)
c=2
Do While i < UBound(strAll)
If (InStr(1, strAll(i), "DAU SNo.-C0", vbTextCompare) > 0) Then
i = i + 4 'Skip 4 lines to get to first SN
Do Until InStr(1, strAll(i), "+", vbTextCompare) > 0 'Loop until line includes "+"
strSNO = Split(strAll(i), "|", -1, vbTextCompare)
i = i + 1
objSheet.Cells(c,1).Offset(1,0).Value = Trim(strSNO(1))
objSheet.Cells(c,2).Offset(1,0).Value = Trim(strSNO(2))
c=c+1
Loop
End If
i = i + 1
Loop
答案 0 :(得分:0)
替换
objSheet.Cells.Offset(1,0).Value = Trim(strSNO(1))
与
objSheet.Cells(i,1).Value = Trim(strSNO(1))
objSheet.Cells(i,2).Value = Trim(strSNO(2))
修改:您确定要strSNO
的字段1和2吗? VBScript数组是从0开始的,因此第一个索引是0,而不是1。
要找到错误,请添加一些调试代码:
On Error Resume Next
objSheet.Cells(i,1).Value = Trim(strSNO(1))
If Err Then
WScript.Echo i & ": " & strAll(i)
WScript.Echo "strSNO(1) = " & strSNO(1)
WScript.Echo "strSNO(1) is of type " & TypeName(strSNO(1))
End If
Err.Clear
objSheet.Cells(i,2).Value = Trim(strSNO(2))
If Err Then
WScript.Echo i & ": " & strAll(i)
WScript.Echo "strSNO(2) = " & strSNO(2)
WScript.Echo "strSNO(2) is of type " & TypeName(strSNO(2))
End If
On Error Goto 0
如果问题证明strAll(i)
某些|
不包含i
,那么Split()
会生成一个只包含一个元素的数组,您可以通过以下方式解决这个问题:
strSNO = Split(strAll(i) & "|", "|", -1, vbTextCompare)