Question

我正在尝试创建一个小脚本，其中包含所选项目的列表，并计算每个所选项目出现在库中其他位置的次数。如果有重复项，则会关闭复选标记，如果这是唯一的副本，则会将其打开。

这很有效。

但我想做的是让它只检查已检查歌曲的库。但是当我在末尾（第三行set行）添加“enabled”位时，脚本会超时。

repeat with entry in selection -- "selection" is a concept implemented in iTunes 
    set a to artist of entry
    set n to name of entry
    set x to count of (file tracks whose name contains n and artist contains a and enabled is true)
    ...
    display dialog x
end repeat

如果我取出and enabled is true它会按预期快速完成，并且结果符合预期。

在行尾有and enabled is true，发生了一些神秘的事情。显然我检错了

Answer 1

以下是一个快速解决方法：

tell application "iTunes"
    repeat with entry in selection -- "selection" is a concept implemented in iTunes 
        set a to artist of entry
        set n to name of entry
        set myTracks to (file tracks whose name contains n and artist contains a)
        set x to {}
        repeat with aTrack in myTracks
            if aTrack's enabled = true then set end of x to aTrack
        end repeat
        display dialog (count x)
    end repeat
end tell

如何使用Applescript计算iTunes中的选中项目

1 个答案: