Question

我需要以下行为：当我开始在窗口中输入时，会出现一个小文本框，其中已经输入了第一个字母，然后在我键入文本后按Enter键文本框应该消失，直到我再次键入该窗口。问题是当我设置Popup1.IsOpen = false文本框仍然保留在窗口中时。

<Window x:Class="Beta.MainWindow"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    Title="MainWindow" Height="350" Width="525" KeyDown="Window_KeyDown_1">  
  <Grid> 
    <Popup Name="Popup1" IsEnabled="True" IsOpen="False" VerticalOffset="-200" HorizontalOffset="50">
       <TextBox Name="tbx" Width="50" KeyDown="tbx_KeyDown" />
     </Popup>
  </Grid>
</Window>

string temp;

private void Window_KeyDown_1(object sender, KeyEventArgs e)
    {
        Popup1.IsOpen = true;
        tbx.Focus();
    }

private void tbx_KeyDown(object sender, KeyEventArgs e)
    {
        if (e.Key == Key.Enter)
        {
            Popup1.IsOpen = false;
            temp = tbx.Text;
            tbx.Text = null;

        }
    }

Answer 1

你应该将e.Handled = true添加到Window KeyDown 1不会被提升并重新打开弹出窗口

   private void tbx_KeyDown(object sender, KeyEventArgs e)
    {
        if (e.Key == Key.Enter)
        {
            Popup1.IsOpen = false;
            temp = tbx.Text;
            tbx.Text = null;
            e.Handled = true;

        }
    }

Answer 2

始终调用Window_KeyDown_1（）方法。你必须设置e.Handled = true

  private void tbx_KeyDown(object sender, KeyEventArgs e)
  {
     if (e.Key == Key.Enter)
     {
        Popup1.IsOpen = false;
        temp = tbx.Text;
        tbx.Text = null;
        e.Handled = true;
     }
  }

popup.isOpen = false后，弹出文本框不会消失

2 个答案: