对于学校编程作业，我构建了一个应用程序，用于在顺序列表对象中存储对象列表。顺序列表类有一个方法可以将新对象插入到列表中，它首先检查列表是否已经允许的最大条目数以及是否返回错误。由于某种原因，我无法在列表中插入新对象（我不断收到“超出最大列表大小”错误），即使其中没有任何条目可以启动。
我使用断点运行它以查看大小数据成员是否以某种方式增加，但这似乎不是这种情况。
请忽略糟糕的代码质量，仍然只是学习...随意提出任何建议：）
这是主程序：
#include<iostream>
#include<string>
#include "aseqlist.h"
using namespace std;
void PrintByGender (const SeqList& L, char gender)
{
int size = L.ListSize();
int count = 0;
while (count < size)
{
if (gender == L.GetData(count).getGender())
{
L.GetData(count).PrintEmployee();
}
count++;
}
}
int InList (const SeqList& L, char *lname, Employee& Emp)
{
int found = 0;
Emp.setLast(lname);
if (L.Find(Emp) == 1)
{
found = 1;
Emp.PrintEmployee();
}
return found;
}
int main()
{
SeqList obj1;
bool close = false;
string choice = "";
do
{
cout << "Please choose what you would like to do: " << "\n";
cout << "N = New record, D = Delete record, P = Print by gender, S = Search and E = Exit" << "\n";
cin >> choice;
cin.ignore();
if (choice == "n" || choice == "N")
{
string first, last;
int age;
char gen;
double empNum;
cout << "First name: ";
cin >> first;
cout << "Last name: ";
cin >> last;
cout << "Age: ";
cin >> age;
cout << "Gender ('M' Or 'F'): ";
cin >> gen;
cout << "Employee Number: ";
cin >> empNum;
Employee newEmp;
newEmp.ReadEmployee(first, last, age, gen, empNum);
obj1.Insert(newEmp);
}
if (choice == "e" || choice == "E")
{
close = true;
}
if (choice == "p" || choice == "P")
{
char genderSearch;
cout << "Male = M, Female = F";
cin >> genderSearch;
cin.ignore();
PrintByGender(obj1, genderSearch);
}
if (choice == "d" || choice == "D")
{
string last;
cout << "Which employee? (Enter Last Name): ";
cin >> last;
cin.ignore();
Employee emp;
emp.setLast(last);
obj1.Delete(emp);
cout << "Deleted";
}
if (choice == "s" || choice == "S")
{
char lnameSearch;
cout << "Last Name?: ";
cin >> lnameSearch;
cin.ignore();
Employee emp;
char *ptrSearch;
ptrSearch = &lnameSearch;
InList(obj1, ptrSearch, emp);
if (emp.getFirst() != "")
{
emp.PrintEmployee();
}
}
}
while (close != true);
};
这是类声明的头文件：
#include <iostream>
using namespace std;
const int MaxListSize = 6;
// You will need to change the typedef in the following line
// from the data type int to Employee
class Employee
{
public:
Employee();
Employee(string firstName, string lastName, int age, char gender, double employeeNumber);
void ReadEmployee(string firstName, string lastName, int age, char gender, double employeeNumber);
char getGender();
string getFirst();
void Employee::setLast(string lname);
string getLast();
void PrintEmployee();
private:
string LastName;
string FirstName;
int Age;
char Gender;
double EmployeeNumber;
};
typedef Employee DataType;
class SeqList
{
private:
// list storage array and number of current list elements
DataType listitem[MaxListSize];
int size;
public:
// constructor
SeqList(void);
// list access methods
int ListSize(void) const;
int ListEmpty(void) const;
int Find (DataType& item) const;
DataType GetData(int pos) const;
// list modification methods
void Insert(const DataType& item);
void Delete(const DataType& item);
DataType DeleteFront(void);
void ClearList(void);
};
// Class Definition:
// constructor. set size to 0
SeqList::SeqList (void): size(6)
{}
// return number of elements in list
int SeqList::ListSize(void) const
{
return size;
}
// tests for an empty list
int SeqList::ListEmpty(void) const
{
return size == 0;
}
// clears list by setting size to 0
void SeqList::ClearList(void)
{
size = 0;
}
// Take item as key and search the list. return True if item
// is in the list and False otherwise. if found,
// assign the list element to the reference parameter item
bool operator==(Employee A, Employee B)
{
bool isequal = false;
if (A.getLast() == B.getLast())
isequal = true;
return isequal;
}
int SeqList::Find(DataType& item) const
{
int i = 0;
if (ListEmpty())
return 0; // return False when list empty
while (i < size && !(item == listitem[i]))
i++;
if (i < size)
{
item = listitem[i]; // assign list element to item
return 1; // return True
}
else
return 0; // return False
}
// insert item at the rear of the list. terminate the program
// if the list size would exceed MaxListSize.
void SeqList::Insert(const DataType& item)
{
// will an insertion exceed maximum list size allowed?
if (size+1 > MaxListSize)
{
cout << "Maximum list size exceeded" << endl;
exit(1);
}
// index of rear is current value of size. insert at rear
listitem[size] = item;
size++; // increment list size
}
// search for item in the list and delete it if found
void SeqList::Delete(const DataType& item)
{
int i = 0;
// search for item
while (i < size && !(item == listitem[i]))
i++;
if (i < size) // successful if i < size
{
// shift the tail of the list to the left one position
while (i < size-1)
{
listitem[i] = listitem[i+1];
i++;
}
size--; // decrement size
}
}
// delete element at front of list and return its value.
// terminate the program with an error message if the list is empty.
DataType SeqList::DeleteFront(void)
{
DataType frontItem;
// list is empty if size == 0
if (size == 0)
{
cout << "Attempt to delete the front of an empty list!" << endl;
exit(1);
}
frontItem = listitem[0]; // get value from position 0.
Delete(frontItem); // delete the first item and shift terms
return frontItem; // return the original value
}
// return value at position pos in list. if pos is not valid
// list position, teminate program with an error message.
DataType SeqList::GetData(int pos) const
{
// terminate program if pos out of range
if (pos < 0 || pos >= size)
{
cout << "pos is out of range!" << endl;
exit(1);
}
return listitem[pos];
}
Employee::Employee()
{
FirstName = "";
LastName = "";
Age = 0;
/*Gender = "";*/
EmployeeNumber = 0;
};
Employee::Employee(string firstName, string lastName, int age, char gender, double employeeNumber)
{
FirstName = firstName;
LastName = lastName;
Age = age;
Gender = gender;
EmployeeNumber = employeeNumber;
};
void Employee::PrintEmployee()
{
cout << "First Name: " << FirstName << "\n";
cout << "Last Name: " << LastName << "\n";
cout << "Age: " << Age << "\n";
cout << "Gender: " << Gender << "\n";
cout << "Employee Number :" << EmployeeNumber << "\n" << "\n";
};
void Employee::ReadEmployee(string firstName, string lastName, int age, char gender, double employeeNumber)
{
FirstName = firstName;
LastName = lastName;
Age = age;
Gender = gender;
EmployeeNumber = employeeNumber;
};
char Employee::getGender()
{
return Gender;
}
string Employee::getFirst()
{
return FirstName;
}
string Employee::getLast()
{
return LastName;
}
void Employee::setLast(string lname)
{
LastName = lname;
}
答案 0 :(得分：3)
构造函数中的问题：
SeqList::SeqList (void): size(6)
尺寸初始化为6。
其他建议。不要将using namespace std;放在头文件中。更好的是，不要将using namespace std;放在任何地方。
答案 1 :(得分：1)
// constructor. set size to 0
SeqList::SeqList (void): size(6)
{}
这是错误的。应该如此：
// constructor. set size to 0
SeqList::SeqList (void): size(0)
{}