Question

我想更改slotList的值。

slotList[1][1] = "1234";

我该如何解决这个问题？

这是我试过的：

JSON：

{

"slotList" : [

      [ "1452", "1452", "1452", "1452", "1452" ],
      [ "1452", "1452", "1452", "1452", "1452" ],
      [ "1452", "1452", "1452", "1452", "1452" ],
      [ "1452", "1452", "1452", "1452", "1452" ],
      [ "1452", "1452", "1452", "1452", "1452" ]
   ]
}

代码：

if (bIsParsed == true)
{
    Json::Value slotList = root["slotList"];

    Json::Value slot = slotList[currentIndex];
    Json::Value value = "111"; // what is wrong? do not change anything! OMG!
    slot[selectIndex].swap(value);
}

Json::StyledWriter writer;
string jsonData = writer.write(root);

Answer 1

的Json ::值及安培; slotList = root [＆＃34; slotList＆＃34;];

的Json ::值及安培; slot = slotList [currentIndex];

slot [selectIndex] =＆＃34; 1111＆＃34 ;;

std :: cout＆lt;＆lt; root.toStyledString（）＆lt;＆lt;的std :: ENDL;

Answer 2

currentIndex需要unsigned。这是API的一个不幸的怪癖，记录为here。（见operator[](int)。）

C ++ JsonCpp从arrayValue更改objectValue

2 个答案: