下面的代码生成Xpath。但是，它不显示@value属性/属性。它工作得不好。
function getXPath(node, path, val) {
path = path || [];
if(node.parentNode) { path = getXPath(node.parentNode, path); }
if(node.previousSibling) {
var count = 1;
var sibling = node.previousSibling
do {
if(sibling.nodeType == 1 && sibling.nodeName == node.nodeName) {count++;}
sibling = sibling.previousSibling;
} while(sibling);
if(count == 1) {count = null;}
} else if(node.nextSibling) {
var sibling = node.nextSibling;
do {
if(sibling.nodeType == 1 && sibling.nodeName == node.nodeName) {
var count = 1;
sibling = null;
} else {
var count = null;
sibling = sibling.previousSibling;
}
} while(sibling);
}
if(node.nodeType == 1) {
if (val){
path.push(node.nodeName.toLowerCase() + (node.id ?
"[@id='"+node.id+"' @value='"+val+"']" :
count > 0 ? "["+count+"]" : ''));
}else{
path.push(node.nodeName.toLowerCase() + (node.id ?
"[@id='"+node.id+"']" : count > 0 ? "["+count+"]" : ''));
}
}
return path;
};