我通过NSData
获得了NSLog
的字符串表示形式,我想再次构建原始NSData
用于测试目的,这是最好的方法吗?< / p>
e.g。
<fe010200 00000000 00011012>
答案 0 :(得分:0)
我猜是这样的:
NSArray *wordStrings =
[string componentsSeparatedByCharactersInSet:
[[NSCharacterSet alphanumericCharacterSet] invertedSet]];
NSMutableData *collectedData = [NSMutableData dataWithCapacity:wordStrings.count * sizeof(unsigned)];
for(NSString *word in wordStrings)
{
NSScanner *scanner = [NSScanner scannerWithString:word];
unsigned newInt;
[scanner scanHexInt:&newInt];
[collectedData appendBytes:&newInt length:sizeof(unsigned)];
}
在使用NSString强制间距后,它会为每个单词创建一个扫描程序,而在扫描程序中执行所有操作会更有效,但它只是用于调试,对吧?通过这种方式,您可以获得wordStrings中点,以确保您对分解字符串的假设是准确的。
答案 1 :(得分:0)
以下是一些对数字进行简单扫描并将其值附加到NSMutableData对象的行
NSString *dataIn = @"<fe010200 00000000 00011012>";
const char *ptr = [dataIn cStringUsingEncoding:NSUTF8StringEncoding];
NSMutableData *data = [NSMutableData data];
while (*ptr) {
unsigned char c1 = *ptr;
ptr++;
if (isalpha(c1))
c1 = (10 + c1 - 'a')<<4;
else if (isnumber(c1))
c1 = (c1 - '0')<<4;
else
continue;
if (!*ptr)
break; // Shouldn't occure -- bad input
unsigned char c2 = *ptr;
ptr++;
if (isalpha(c2))
c2 = 10 + c2 - 'a';
else if (isnumber(c2))
c2 = c2 - '0';
c1 = c1 | c2;
[data appendBytes:&c1 length:1];
}
NSLog(@"%@", data);