我编写了一个程序，它使用了大多数math.h库函数来创建一种科学计算器。但是，我没有得到所需的输出。我总是在输出结束时得到0.000000。请帮我辨别我的错误，谢谢。
#include <stdio.h>
#include <math.h>
#define PI 3.14159265
float sine(float x);
float cosine(float x);
float tangent(float x);
float sineh(float x);
float cosineh(float x);
float tangenth(float x);
float logten(float x);
float squareroot(float x);
float exponent(float x);
float power(float x,float y);
int main()
{
int x,y,n,answer;
printf("What do you want to do?\n");
printf("1.sin 2.cos 3. tan 4. sinh 5.cosh 6.tanh 7.1og10 8. square root. 9.exponent 10.power.");
scanf ("%d",&n);
if (n<9 && n>0)
{
printf("\n What is x? ");
scanf("%f",&x);
switch (n)
{
case 1: answer = sine(x); break;
case 2: answer = cosine(x); break;
case 3: answer = tangent(x); break;
case 4: answer = sineh(x); break;
case 5: answer = cosineh(x); break;
case 6: answer = tangenth(x); break;
case 7: answer = logten(x); break;
case 8: answer = squareroot(x); break;
case 9: answer = exponent(x); break;
}
}
if (n==10)
{
printf("What is x and y?\n");
scanf("%f%f",&x,&y);
answer = power(x,y);
}
if (n>0 && n<11)
printf("%f",answer);
else
printf("Wrong input.\n");
return 0;
}
float sine(float x)
{
return (sin (x*PI/180));
}
float cosine(float x)
{
return (cos (x*PI/180));
}
float tangent(float x)
{
return (tan(x*PI/180));
}
float sineh(float x)
{
return (sinh(x));
}
float cosineh(float x)
{
return (sinh(x));
}
float tangenth(float x)
{
return (sinh(x));
}
float logten(float x)
{
return (log10(x));
}
float squareroot(float x)
{
return (sqrt(x));
}
float exponent(float x)
{
return(exp(x));
}
float power(float x, float y)
{
return (pow(x,y));
}
答案 0 :(得分：4)
您已将这四个变量声明为整数：
int x,y,n,answer;
但n是您实际视为整数的唯一一个。将x，y和answer声明为float：
int n;
float x, y, answer;
答案 1 :(得分：4)
#include <stdio.h>
#include <math.h>
#include<conio.h>
#define PI 3.14159265
float sine(float x)
{
return (sin (x*PI/180));
}
float cosine(float x)
{
return (cos (x*PI/180));
}
float tangent(float x)
{
return (tan(x));
}
float sineh(float x)
{
return (sinh(x));
}
float cosineh(float x)
{
return (sinh(x));
}
float tangenth(float x)
{
return (sinh(x));
}
float logten(float x)
{
return (log10(x));
}
float squareroot(float x)
{
return (sqrt(x));
}
float exponent(float x)
{
return(exp(x));
}
float power(float x, float y)
{
return (pow(x,y));
}
int main(void)
{
int n;
float x,y,answer;
printf("What do you want to do?\n");
printf("1.sin 2.cos 3. tan 4. sinh 5.cosh 6.tanh 7.1og10 8. square root.
9.exponent 10.power.");
scanf ("%d",&n);
if (n<9 && n>0)
{
printf("\n What is x? ");
scanf("%f",&x);
switch (n)
{
case 1: answer = sine(x); break;
case 2: answer = cosine(x); break;
case 3: answer = tangent(x); break;
case 4: answer = sineh(x); break;
case 5: answer = cosineh(x); break;
case 6: answer = tangenth(x); break;
case 7: answer = logten(x); break;
case 8: answer = squareroot(x); break;
case 9: answer = exponent(x); break;
}
}
if (n==10)
{
printf("What is x and y?\n");
scanf("%f%f",&x,&y);
answer = power(x,y);
}
if (n>0 && n<11)
printf("%f",answer);
else
printf("Wrong input.\n");
getch();
return 0;
}
答案 2 :(得分：2)
如果我启用了-Wall和-Wconversion，我会看到以下警告，如果你解决了，它将解决你的问题：
foo.c:23:14: warning: format specifies type 'float *' but the argument has type 'int *' [-Wformat]
scanf("%f",&x);
~~ ^~
%d
foo.c:26:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 1: answer = sine(x); break;
~ ^~~~~~~
foo.c:27:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 2: answer = cosine(x); break;
~ ^~~~~~~~~
foo.c:28:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 3: answer = tangent(x); break;
~ ^~~~~~~~~~
foo.c:29:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 4: answer = sineh(x); break;
~ ^~~~~~~~
foo.c:30:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 5: answer = cosineh(x); break;
~ ^~~~~~~~~~
foo.c:31:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 6: answer = tangenth(x); break;
~ ^~~~~~~~~~~
foo.c:32:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 7: answer = logten(x); break;
~ ^~~~~~~~~
foo.c:33:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 8: answer = squareroot(x); break;
~ ^~~~~~~~~~~~~
foo.c:34:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 9: answer = exponent(x); break;
~ ^~~~~~~~~~~
foo.c:40:16: warning: format specifies type 'float *' but the argument has type 'int *' [-Wformat]
scanf("%f%f",&x,&y);
~~ ^~
%d
foo.c:40:19: warning: format specifies type 'float *' but the argument has type 'int *' [-Wformat]
scanf("%f%f",&x,&y);
~~ ^~
%d
foo.c:41:12: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
answer = power(x,y);
~ ^~~~~~~~~~
foo.c:44:15: warning: format specifies type 'double' but the argument has type 'int' [-Wformat]
printf("%f",answer);
~~ ^~~~~~
%d
foo.c:51:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (sin (x*PI/180));
~~~~~~ ^~~~~~~~~~~~~~
foo.c:55:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (cos (x*PI/180));
~~~~~~ ^~~~~~~~~~~~~~
foo.c:59:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (tan(x*PI/180));
~~~~~~ ^~~~~~~~~~~~~
foo.c:63:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (sinh(x));
~~~~~~ ^~~~~~~
foo.c:67:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (sinh(x));
~~~~~~ ^~~~~~~
foo.c:71:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (sinh(x));
~~~~~~ ^~~~~~~
foo.c:75:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (log10(x));
~~~~~~ ^~~~~~~~
foo.c:79:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (sqrt(x));
~~~~~~ ^~~~~~~
foo.c:83:9: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return(exp(x));
~~~~~~ ^~~~~~
foo.c:87:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (pow(x,y));
~~~~~~ ^~~~~~~~
24 warnings generated.
答案 3 :(得分：1)
您将x和其他变量声明为int。尝试声明为float而不是
答案 4 :(得分：0)
问题是格式说明符错误。将%f语句中的所有%d更改为scanf。