Question

您需要帮助撰写查询。

表格是：

tblStandard1students
tblStandard2students
tblStandard1students
tblDivision
tblCandidateinfo

tblStandard1students，tblStandard2students，tblStandard1studentstbl包含有关参加标准1,2和3的学生的信息

tblStandars1students

Candid  admitted
  1        Y
  2        N
  3        Y

tblDivision只包含2列

 ID     Division
  1       A
  2       B
  3       C

tblCandidateinfo

Candid  gender Division
  1       M      1
  2       F      2

依旧......

现在我想要像这样的表

Division  Students(Standard1)  Students(Standard2)  Students(Standard3)
           M           F         M          F        M          F
------------------------------------------------------------------------
 A         1           0         0          0         0         1
 B         2           2         3          3         4         4
 C         1           0         0          0         0         0

我尝试了以下查询：

SELECT Division,

    ( SELECT count(*)
     FROM tblStandard1students A
     INNER JOIN tblCandidateinfo B ON A.Candid=B.Candid
     INNER JOIN tblDivision C ON C.ID=B.Division) AS Students(Standard1),

    ( SELECT count(*)
     FROM tblStandard2students A
     INNER JOIN tblCandidateinfo B ON A.Candid=B.Candid
     INNER JOIN tblDivision C ON C.ID=B.Division) AS Students(Standard2),

    ( SELECT count(*)
     FROM tblStandard3students A
     INNER JOIN tblCandidateinfo B ON A.Candid=B.Candid
     INNER JOIN tblDivision C ON C.ID=B.Division ) AS Students(Standard3)
FROM tblDivision Z

但这只是查询的一半，我明智地将其性别分开......帮助我完成它。

Answer 1

;WITH combined AS
(
    SELECT ci.Division, 'Students(Standard1) ' + ci.gender AS grp
    FROM tblCandidateInfo ci
    INNER JOIN tblStandard1students s ON ci.Candid = s.Candid
    UNION ALL
    SELECT ci.Division, 'Students(Standard2) ' + ci.gender AS grp
    FROM tblCandidateInfo ci
    INNER JOIN tblStandard2students s ON ci.Candid = s.Candid
    UNION ALL
    SELECT ci.Division, 'Students(Standard3) ' + ci.gender AS grp
    FROM tblCandidateInfo ci
    INNER JOIN tblStandard1studentstbl s ON ci.Candid = s.Candid
)
SELECT Division, 
    [Students(Standard1) M], [Students(Standard1) F],
    [Students(Standard2) M], [Students(Standard2) F],
    [Students(Standard3) M], [Students(Standard3) F]
FROM
(
    SELECT d.Division, grp
    FROM tblDivision d
    LEFT OUTER JOIN combined c ON d.ID = c.Division
) x
PIVOT
(
    COUNT(grp)
    FOR grp IN ([Students(Standard1) M], [Students(Standard1) F],
        [Students(Standard2) M], [Students(Standard2) F],
        [Students(Standard3) M], [Students(Standard3) F])
) y
ORDER BY Division

Answer 2

SELECT divison.Division，IFNULL（stander1.M，0），IFNULL（stander1.F，0）FROM test。tblDivision divison 左连接（SELECT除法，计数（情况性别为'M'，然后1，否则为空结束）为M，计数（案例性别为'F'，然后1为其他为空结束）为F 从 test。tblCandidateinfo tc内联接test.tblStandars1students ts1

ON tc.Candid = ts1.Candid

group by division) as stander1 on stander1.division= divison.id

group by divison.id ;

感染IFNULL使用ISNULL和对所有标准表进行左连接

Sql Query从不同的表中查找总和

2 个答案: