用于检查连续数字的Java方法

Question

我需要编写一个名为consecutive的方法，该方法接受6个参数来检查6个输入是否是连续数，而不管顺序如何。如果数字是连续的，则返回true，否则返回false。有人可以教我这样做的最有效方法是什么？我尝试过这种方法，但如果我有6个数字会效率低吗？

public static boolean consecutive(int numberOne,int numberTwo,int numberThree) {
    if(((numberTwo==numberOne-1) && (numberThree== numberTwo-1)) || ((numberTwo==numberOne+1) && (numberThree==numberTwo+1)) || ((numberTwo==numberOne+2) &&( numberThree==numberOne+1)) || ((numberTwo==numberOne-1)&& (numberThree==numberOne+1)) || ((numberTwo==numberOne-2) && (numberThree==numberOne-1)) ||((numberTwo==numberOne+1) && (numberThree==numberOne-1))){
        return true;
    }else{
        return false;
    }
}

}

Answer 1

将值添加到数组中，对数组进行排序，然后测试一组连续的值：

int[] test = new int[] {numberOne, numberTwo, etc...};
Arrays.sort(test);
for (int i = 0; i < test.length - 1; i++) {
  if (test[i] + 1 != test[i + 1]) {
    // Not sequential
  }
}

Answer 2

增强@Chris的答案，假设没有重复的数字：

public static boolean consecutive(
  int numberOne,int numberTwo,int numberThree, 
  int numberFour, int numberFive, int numberSix) {

 int [] ns = { 
   numberOne, numberTwo, numberThree, 
   numberFour, numberFive, numberSix };

 Arrays.sort(ns);

 return ( ns[ns.length-1] - ns[0] == ns.length-1 );
}