Question

我在symfony 2.0中实现了多个数据库概念。现在我需要在依赖注入概念的myservice.php文件中动态获取实体管理器。我怎么称呼这个实体经理？

services.xml：

        <container xmlns="http://symfony.com/schema/dic/services"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://symfony.com/schema/dic/services                                 http://symfony.com     /schema/dic/services/services-1.0.xsd">

<services>
    <service id="my_service" class="Traxcrm\SalesBundle\Services\MyService">
        <argument type="service" id="doctrine" />
    </service>
 </services>

 </container>

mysevice.php

class MyService  {

private $doctrine;

public function __construct(Doctrine\Bundle\DoctrineBundle\Registry $doctrine)
{

    $this->doctrine = $doctrine;            

}
class MyService {

 private $doctrine;

 public function __construct(Doctrine\Bundle\DoctrineBundle\Registry $doctrine) {

     $this->doctrine = $doctrine;
 }

 public function getUserDetails($id) {

     $query = $this->doctrine->getEntityManager('Test')->createQuery("SELECT        p            FROM        TraxcrmSigninBundle:Tblallusers p where p.id=$id");
    $userDetails = $query->getArrayResult();

    return $userDetails;
}

Answer 1

设置服务并注入学说：

服务定义（services.yml或config.yml）：

services:
    service_name:
        class: <namespace>myservice.php
        arguments: ['@doctrine']

或xml：

<services>
    <service id="service_name" class="<namespace>myservice.php">
        <argument type="service" id="doctrine"/>
    </service>
</services>

然后设置你的类来接受传递的学说对象

public class myservice {

   private $doctrine;

   public function __construct(Doctrine\Bundle\DoctrineBundle\Registry $doctrine) {
       $this->doctrine = $doctrine;
   }

   public function aFunction() {
       $em = $this->doctrine->getEntityManager('<name>')......
   }
}

依赖注入中的动态数据库

1 个答案: