Question

我有一个曾经工作的表值函数，但不再存在或者至少花费很多时间。

唯一可能改变的是查询读取的表上的数据量。

这是该功能的代码。

ALTER FUNCTION [dbo].[SUPERVISOR_NOMINA2] (@iniDATE DATE,@endDATE DATE)
RETURNS @TABLA TABLE (
     [ID]               INT         NOT NULL PRIMARY KEY CLUSTERED
    ,[EFEC]             FLOAT       NOT NULL
    ,[TOP]              FLOAT       NOT NULL
    ,[EXTRA]            FLOAT       NOT NULL
    ,[DEUDA]            FLOAT       NOT NULL
    )

AS 
BEGIN

    INSERT INTO @tempTABLE

    /*------RUN FROM HERE TO TEST-------
    DECLARE @iniDATE DATE,@endDATE DATE
    SET @iniDATE = '2013-02-20'
    --*/

    SELECT 
    SOURCE.[ID],SOURCE.[NAME],SOURCE.[CAMPAIGN],[SUPERVISOR],[FLOOR MANAGER],[LAST LOGON],[EFEC],[TOP]
        ,[HR+] AS EXTRA
        ,CASE
            WHEN [DIF] >= 0 THEN 0
            ELSE [DIF]
        END AS DEUDA
    FROM (
    SELECT  
           NM.[ID]
          ,NM.[NAME]
          ,NM.[CAMPAIGN]
          ,NM.[SUPERVISOR]
          ,SUM(CASE 
             WHEN [ATT ID] > 4 AND [ATT ID] <> 7 THEN '0'
             ELSE ROUND([EFEC],2)
          END) AS [EFEC]
          ,SUM(CASE 
             WHEN [ATT ID] > 4 AND [ATT ID] <> 7 THEN '0'
             ELSE [TOP]
          END) AS [TOP]
          ,SUM(CASE 
             WHEN [ATT ID] > 4 AND [ATT ID] <> 7 THEN '0'
             WHEN [EFEC] < [TOP] THEN 0
             WHEN [TOP]+[EXHR] > [EFEC] THEN ROUND([EFEC]-([TOP]+[EXHR]),0,1)
             ELSE [EXHR]
          END) AS [HR+]
          ,ROUND(SUM(CASE 
             WHEN [ATT ID] > 4 AND [ATT ID] <> 7 THEN '0'
             WHEN [EFEC] < [TOP] THEN ROUND([EFEC]-[TOP],2)
             WHEN [TOP]+[EXHR] > [EFEC] THEN ROUND([EFEC]-([TOP]+ROUND([EFEC]-([TOP]+[EXHR]),0,1)),2)
             ELSE ROUND([EFEC]-([TOP]+[EXHR]),2)
          END),2) AS [DIF]

      FROM [WFO].[dbo].[VIEW_NOMINA] NM
      FULL JOIN [WFO].[dbo].[VIEW_ATTENDANCE] AT ON NM.ID = AT.ID AND NM.DATE = AT.DATE
      WHERE NM.DATE < CONVERT(DATE,GETDATE()) AND NM.[DATE] BETWEEN @iniDATE AND @endDATE
      GROUP BY NM.[ID],NM.[NAME],NM.[CAMPAIGN],NM.[SUPERVISOR]) SOURCE
      LEFT JOIN (
          SELECT [ID],CONVERT(DATE,MAX(DATETIME)) AS [LAST LOGON]
          FROM [WFO].[dbo].[AGENT-LOGBOOK] 
          GROUP BY [ID]
      ) LT ON LT.ID = SOURCE.ID
      LEFT JOIN [WFO].[dbo].[SUPERVISORS] SP ON SP.NAME = SOURCE.SUPERVISOR
      ORDER BY [NAME]
RETURN
END

有趣的是，如果我只是在insert语句之后和return语句之前运行查询，那么查询将在几秒钟内完成。

你有什么建议我做错了？

Answer 1

一个可能的问题是你的where子句中的这个SQL：

NM.DATE < CONVERT(DATE,GETDATE())

除了在这种情况下我非常确定CONVERT是不必要的这一事实之外，以这种方式使用函数通常可以使得你所使用的索引不会被使用。

Answer 2

这甚至可以运行吗？许多CASE语句为一个案例返回一个字符，为另一个案例返回一个数字。这应该失败。改变所有这样的行

 WHEN [ATT ID] > 4 AND [ATT ID] <> 7 THEN '0'

到这个

 WHEN [ATT ID] > 4 AND [ATT ID] <> 7 THEN 0

表值函数

2 个答案: